Plane Geometry
-  In a triangle ABC, ∠BAC = 90° and AD is perpendicular to BC. If AD = 6 cm and BD = 4 cm, then the length of BC is
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                        View Hint View Answer Discuss in Forum On the basis of question we draw a figure of triangle ABC ,  
 ∠BAC = 90°
 AB = √AD² + BD²
 AB = √6² + 4²
 AB = √36 + 16 = √52 cm
 ∆ABD and ∆ABC are similar.Correct Option: DOn the basis of question we draw a figure of triangle ABC ,  
 ∠BAC = 90°
 AB = √AD² + BD²
 AB = √6² + 4²
 AB = √36 + 16 = √52 cm
 ∆ABD and ∆ABC are similar.∴ AB = BD BC AB 
 ⇒ AB² = BC × BD
 ⇒ 52 = BC × 4
 ⇒ BC = 52 ÷ 4 = 13 cm
-  In ∆ ABC, ∠BAC = 90° and AB = 1 BC.Then the measure of ∠ACB is : 2 
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                        View Hint View Answer Discuss in Forum On the basis of question we draw a figure of triangle ABC ,  
 Let AB = k ; BC = 2k units
 ⇒ AC = √4k² - k² = √3k
 Correct Option: BOn the basis of question we draw a figure of triangle ABC ,  
 Let AB = k ; BC = 2k units
 ⇒ AC = √4k² - k² = √3k∴ ∠ACB = AB = 1 = sin30° BC 2 
 ∴ ∠ACB = 30°
-  The ratio of the angles of a triangle is 1 : 2 : 3 .Then the smallest angle is : 3 
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                        View Hint View Answer Discuss in Forum As per the given in question, 
 In a ∆ ABC,∠A : ∠B : ∠C = 1 : 2 : 3 = 3 : 2 : 9 3 
 Sum of the terms of ratio = 3 + 2 + 9 = 14∴ Lowest angle = ∠B = 2 × 180° 14 
 Correct Option: CAs per the given in question, 
 In a ∆ ABC,∠A : ∠B : ∠C = 1 : 2 : 3 = 3 : 2 : 9 3 
 Sum of the terms of ratio = 3 + 2 + 9 = 14∴ Lowest angle = ∠B = 2 × 180° 14 Lowest angle = ∠B = 180° = 25 5° 7 7 
-  In a triangle, the distance of the centroid from the three vertices is 4 cm, 6 cm and 8 cm respectively. Then the length of the smallest median is :
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                        View Hint View Answer Discuss in Forum On the basis of question we draw a figure of triangle ABC and the distance of the centroid from the three vertices is 4 cm, 6 cm and 8 cm respectively,  
 AO = 4 cm.⇒ 2 AD = 4 3 ⇒ AD = 4 × 3 = 6 cm. 2 
 BO = 6 cm.⇒ BE = 3 × 6 = 9 cm. 2 
 CO = 8 cm.
 Correct Option: COn the basis of question we draw a figure of triangle ABC and the distance of the centroid from the three vertices is 4 cm, 6 cm and 8 cm respectively,  
 AO = 4 cm.⇒ 2 AD = 4 3 ⇒ AD = 4 × 3 = 6 cm. 2 
 BO = 6 cm.⇒ BE = 3 × 6 = 9 cm. 2 
 CO = 8 cm.⇒ CF = 8 × 3 = 12 cm. 2 
-  The point of intersection of all the three medians of a triangle is called its
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                        View Hint View Answer Discuss in Forum We can say that the point of intersection of the medians of a triangle is called centroid. Correct Option: CWe can say that the point of intersection of the medians of a triangle is called centroid. Hence , required answer is centroid . 
 
	