Plane Geometry


  1. In a triangle ABC, ∠BAC = 90° and AD is perpendicular to BC. If AD = 6 cm and BD = 4 cm, then the length of BC is









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    On the basis of question we draw a figure of triangle ABC ,

    ∠BAC = 90°
    AB = √AD² + BD²
    AB = √6² + 4²
    AB = √36 + 16 = √52 cm
    ∆ABD and ∆ABC are similar.

    Correct Option: D

    On the basis of question we draw a figure of triangle ABC ,

    ∠BAC = 90°
    AB = √AD² + BD²
    AB = √6² + 4²
    AB = √36 + 16 = √52 cm
    ∆ABD and ∆ABC are similar.

    AB
    =
    BD
    BCAB

    ⇒ AB² = BC × BD
    ⇒ 52 = BC × 4
    ⇒ BC = 52 ÷ 4 = 13 cm


  1. In ∆ ABC, ∠BAC = 90° and AB =
    1
    BC.Then the measure of ∠ACB is :
    2









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    On the basis of question we draw a figure of triangle ABC ,

    Let AB = k ; BC = 2k units
    ⇒ AC = √4k² - k² = √3k

    Correct Option: B

    On the basis of question we draw a figure of triangle ABC ,

    Let AB = k ; BC = 2k units
    ⇒ AC = √4k² - k² = √3k

    ∴ ∠ACB =
    AB
    =
    1
    = sin30°
    BC2

    ∴ ∠ACB = 30°



  1. The ratio of the angles of a triangle is 1 :
    2
    : 3 .Then the smallest angle is :
    3









  1. View Hint View Answer Discuss in Forum

    As per the given in question,
    In a ∆ ABC,

    ∠A : ∠B : ∠C = 1 :
    2
    : 3 = 3 : 2 : 9
    3

    Sum of the terms of ratio = 3 + 2 + 9 = 14
    ∴ Lowest angle = ∠B =
    2
    × 180°
    14

    Correct Option: C

    As per the given in question,
    In a ∆ ABC,

    ∠A : ∠B : ∠C = 1 :
    2
    : 3 = 3 : 2 : 9
    3

    Sum of the terms of ratio = 3 + 2 + 9 = 14
    ∴ Lowest angle = ∠B =
    2
    × 180°
    14

    Lowest angle = ∠B =
    180°
    = 25
    77


  1. In a triangle, the distance of the centroid from the three vertices is 4 cm, 6 cm and 8 cm respectively. Then the length of the smallest median is :









  1. View Hint View Answer Discuss in Forum

    On the basis of question we draw a figure of triangle ABC and the distance of the centroid from the three vertices is 4 cm, 6 cm and 8 cm respectively,

    AO = 4 cm.

    2
    AD = 4
    3

    ⇒ AD =
    4 × 3
    = 6 cm.
    2

    BO = 6 cm.
    ⇒ BE =
    3 × 6
    = 9 cm.
    2

    CO = 8 cm.

    Correct Option: C

    On the basis of question we draw a figure of triangle ABC and the distance of the centroid from the three vertices is 4 cm, 6 cm and 8 cm respectively,

    AO = 4 cm.

    2
    AD = 4
    3

    ⇒ AD =
    4 × 3
    = 6 cm.
    2

    BO = 6 cm.
    ⇒ BE =
    3 × 6
    = 9 cm.
    2

    CO = 8 cm.
    ⇒ CF =
    8 × 3
    = 12 cm.
    2



  1. The point of intersection of all the three medians of a triangle is called its









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    We can say that the point of intersection of the medians of a triangle is called centroid.

    Correct Option: C

    We can say that the point of intersection of the medians of a triangle is called centroid. Hence , required answer is centroid .