In ∆ ABC, ∠BAC = 90° and AB = 1BC.Then the measure

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On the basis of question we draw a figure of triangle ABC ,

Let AB = k ; BC = 2k units
⇒ AC = √4k² - k² = √3k

∴ ∠ACB =	AB	=	1	= sin30°
	BC		2

∴ ∠ACB = 30°

In ∆ ABC, ∠BAC = 90° and AB =	1	BC.Then the measure of ∠ACB is :
	2