Electric circuits miscellaneous
- In the circuit shown below, if the current through the resistor R is zero, what is the value of I?
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When only voltage source
Using KVL in loop (1)
16 – 2 (i1 + i2) – 2i2 = 0
⇒ i1 + 2i2 = 8 ...(i)
Using KVL in loop (2)
16 – 2 (i1 + i2) – 4i1 = 0
3i1 + i2 = 8 ...(ii)
Solving equations (i) and (ii)
l2 = 2l1
Putting in equation (i)
i1 + 4i1 = 8
⇒ i1 = 1.6 Amp
When only current sourcei1' = 2I = 0.4I Amp 2 + 3
Total current through R is zero.
Using superposition theorem
∴ i1 – i1' = 0
⇒ 1.6 – 0.4 I = 0
⇒ I = 4 AmpCorrect Option: D
When only voltage source
Using KVL in loop (1)
16 – 2 (i1 + i2) – 2i2 = 0
⇒ i1 + 2i2 = 8 ...(i)
Using KVL in loop (2)
16 – 2 (i1 + i2) – 4i1 = 0
3i1 + i2 = 8 ...(ii)
Solving equations (i) and (ii)
l2 = 2l1
Putting in equation (i)
i1 + 4i1 = 8
⇒ i1 = 1.6 Amp
When only current sourcei1' = 2I = 0.4I Amp 2 + 3
Total current through R is zero.
Using superposition theorem
∴ i1 – i1' = 0
⇒ 1.6 – 0.4 I = 0
⇒ I = 4 Amp
- Two incandescent light bulbs of 40 W and 60W rating are connected in series across the mains. Then
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NA
Correct Option: D
NA
- The maximum value of mutual inductance of two inductively coupled coils with selfinductance, L1 = 49 mH and L2 = 81 mH is
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M < k √L1 L2
⇒ Mmax = k √L1 L2
= √L1 L2 = √40 × 81 = 63 mHCorrect Option: B
M < k √L1 L2
⇒ Mmax = k √L1 L2
= √L1 L2 = √40 × 81 = 63 mH
- From the graphs drawn below, which of the following is non-planer?
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This graph is non planar, as it can not be drawn on sheet of paper without using crossing lines .
Correct Option: C
This graph is non planar, as it can not be drawn on sheet of paper without using crossing lines .
- If the number of branches in a network is B, the number of nodes is N and the number of dependent loops is L, then the number of independent node equations will be
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NA
Correct Option: D
NA