Electric circuits miscellaneous


Electric circuits miscellaneous

  1. In the series Rc circuit shown in the figure, the voltage across C starts increasing when the d.c. source is switched on. The rate of increase of voltage across C at the instant just after the switch is closed (i.e. at t = 0+) will be










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    Voltage across the capacitor at any time t, Vc = V (l – e– t / RC)
    = l – e– t / RC ... (since V = 1 volt)

    dVc
    =
    1
    e– t / RC
    dtRC

    At t = 0+ ,
    dVc
    =
    1
    dtRC

    Correct Option: D

    Voltage across the capacitor at any time t, Vc = V (l – e– t / RC)
    = l – e– t / RC ... (since V = 1 volt)

    dVc
    =
    1
    e– t / RC
    dtRC

    At t = 0+ ,
    dVc
    =
    1
    dtRC


  1. A periodic rectangular signal X(t) has the wave form shown in the figure. Frequency of the fifth harmonic of its spectrum is










  1. View Hint View Answer Discuss in Forum

    Periodic time = 4 ms = 4 × 10 – 3 sec.

    Fundamental frequency =
    103
    = 250 Hz
    4

    ∴ Frequency of the 5th harmonic = 250 × 5 = 1250 Hz

    Correct Option: D

    Periodic time = 4 ms = 4 × 10 – 3 sec.

    Fundamental frequency =
    103
    = 250 Hz
    4

    ∴ Frequency of the 5th harmonic = 250 × 5 = 1250 Hz



  1. In the given figure, A1, A2 and A3 are ideal ammeters. If A1 reads 5A, A2 reads 12 A, then A3 should read










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    Since the source is an a.c voltage, therefore
    I 3rms = √I1rms ² + I2rms ²
    = √5² +12² = 13 A

    Correct Option: C

    Since the source is an a.c voltage, therefore
    I 3rms = √I1rms ² + I2rms ²
    = √5² +12² = 13 A


  1. The voltage VC1, VC2 and VC3 across the capacitors in the circuit in the given figure, under steady state are respectively










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    In steady state, capacitors are open and inductances are short.

    For VC1

    VC1 = 100 ×
    40
    = 80 V
    50

    For VC2 and VC3
    VC2 = 80 ×
    C3
    C2 + C3

    = 80 ×
    3
    = 48 V
    5

    VC3 = 80 ×
    C2
    C2 + C3

    = 16 × 2 = 32 V

    Correct Option: B

    In steady state, capacitors are open and inductances are short.

    For VC1

    VC1 = 100 ×
    40
    = 80 V
    50

    For VC2 and VC3
    VC2 = 80 ×
    C3
    C2 + C3

    = 80 ×
    3
    = 48 V
    5

    VC3 = 80 ×
    C2
    C2 + C3

    = 16 × 2 = 32 V



  1. When the angular frequency ω in the given figure is varied from 0 to ∞ , the locus of the current phasor I2 is given by









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    I2(ω) =
    Em cosωt
    R2 +
    1
    jωC



    At ω = ∞ , I2ω =
    Em
    R2

    Also, I2 is leading with voltage phasor.
    At ω = 0, I2 (0) = 0
    Thus desired locus should be as shown.

    Correct Option: A

    I2(ω) =
    Em cosωt
    R2 +
    1
    jωC



    At ω = ∞ , I2ω =
    Em
    R2

    Also, I2 is leading with voltage phasor.
    At ω = 0, I2 (0) = 0
    Thus desired locus should be as shown.