Electric circuits miscellaneous


Electric circuits miscellaneous

  1. A certain network N feeds a load resistance R as shown in the Fig. (a) It consumes a power of P W. If an identical network is added as shown in Fig. (b) then power consumed by R will be










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    Let network N contains a resistance R and voltage V, then Fig. (a) is redrawn as below.

    and P =
    V
    2 =
    V2
    2R4R

    Now, redrawing Fig. (b), we have
    power dissipated in R = P = V (2I)2 R

    P' =
    2V
    2R =
    4V2
    =
    16
    P
    3R9R9

    Hence, P < P' < 4P

    Correct Option: C

    Let network N contains a resistance R and voltage V, then Fig. (a) is redrawn as below.

    and P =
    V
    2 =
    V2
    2R4R

    Now, redrawing Fig. (b), we have
    power dissipated in R = P = V (2I)2 R

    P' =
    2V
    2R =
    4V2
    =
    16
    P
    3R9R9

    Hence, P < P' < 4P


  1. For a 2-port symmetrical bilateral network, if transmission parameters A = 3 and B = 1 Ω, then value of parameter C is









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    For symmetrical network
    A = D = 3
    For bilateral
    AD – BC = 1
    ∴ 9 – C = 1
    ⇒ C = 8 Ω

    Correct Option: B

    For symmetrical network
    A = D = 3
    For bilateral
    AD – BC = 1
    ∴ 9 – C = 1
    ⇒ C = 8 Ω



  1. For the network shown below, Z-parameter will be











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    Using KVL,

    V1(s) =
    1
    + sL1I1(s) + SM.I2(s)
    sC

    and V2 (s) = (R + SL2) I 2 (s) + SM I 1 (s)
    then

    Correct Option: A

    Using KVL,

    V1(s) =
    1
    + sL1I1(s) + SM.I2(s)
    sC

    and V2 (s) = (R + SL2) I 2 (s) + SM I 1 (s)
    then


  1. For latice type attenuator shown in the given figure, the characteristic impedance R0 is










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    Characteristic impedance, R0 = √Rsc Roc

    Since Rsc = 2
    R1 R2
    , Roc =
    R1 R2
    R1 + R22

    ∴ R0 = √R1 R2

    Correct Option: C

    Characteristic impedance, R0 = √Rsc Roc

    Since Rsc = 2
    R1 R2
    , Roc =
    R1 R2
    R1 + R22

    ∴ R0 = √R1 R2



  1. Y parameters of a four terminal block are 42A single element of 1 ohm
    11

    is connected across as shown in the given figure. The new Y parameters will be










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    Y parameter of two networks in parallel are sums of the corresponding Y-parameters.

    As Y1 = 1-1
    -11

    Y2 = 42
    11

    ∴ Y = Y1 + Y2 = 51
    02

    Correct Option: A

    Y parameter of two networks in parallel are sums of the corresponding Y-parameters.

    As Y1 = 1-1
    -11

    Y2 = 42
    11

    ∴ Y = Y1 + Y2 = 51
    02