Electric circuits miscellaneous
-  In the delta equivalent of the given star connected circuit, ZOR is equal to 
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                        View Hint View Answer Discuss in Forum ZQR = 5 × 10 + 10 × j10 + j10 × 5 = (10 + j30 ) Ω 5 Correct Option: DZQR = 5 × 10 + 10 × j10 + j10 × 5 = (10 + j30 ) Ω 5 
-  A delta connected network with Y-equivalent is shown below. 
 The resistances R1, R2, R3 (in ohms) are respectively
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                        View Hint View Answer Discuss in Forum R1 = Rab Rac = 150 = 3 Rab + Rac + Rbc 50 R2 = Rab Rac = 5 × 25 = 1.5 Rab + Rac + Rbc 50 R3 = 30 × 15 = 9 50 
 Correct Option: DR1 = Rab Rac = 150 = 3 Rab + Rac + Rbc 50 R2 = Rab Rac = 5 × 25 = 1.5 Rab + Rac + Rbc 50 R3 = 30 × 15 = 9 50 
 
-  In the given figure, the switch was closed for a long time before opening at t = 0. The voltage Vx at t = 0+ is 
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                        View Hint View Answer Discuss in Forum At t = 0+ , the circuit will be as shown below.  
 I L (0+) = 0
 Then Vi = – 50 VCorrect Option: CAt t = 0+ , the circuit will be as shown below.  
 I L (0+) = 0
 Then Vi = – 50 V
-  In a passive two-port network, the open-circuit impedance matrix is  10 2  5 2 
 If input port is interchanged with the output port, then open-circuit impedance matrix will be
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                        View Hint View Answer Discuss in Forum The port-equations are 
 V1 = 10 I 1 + 2I 2 ....(i)
 V2 = 2I 1 + 5 I2 ....(ii)
 Rewriting equations (i) and (ii) as
 V2 = 5 I2 + 2I1 ....(iii)
 V1 = 2 I2 + 10 I1 ....(iv)
 Writing in matrix form V2  =  5 2   I2  V1 2 10 I1 
 Correct Option: BThe port-equations are 
 V1 = 10 I 1 + 2I 2 ....(i)
 V2 = 2I 1 + 5 I2 ....(ii)
 Rewriting equations (i) and (ii) as
 V2 = 5 I2 + 2I1 ....(iii)
 V1 = 2 I2 + 10 I1 ....(iv)
 Writing in matrix form V2  =  5 2   I2  V1 2 10 I1 
 
-  An ideal transformer has turns ratio of 2 : 1. Considering high voltage side as port 1 and low voltage side as port 2, then transmission line parameters of transformer will be
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                        View Hint View Answer Discuss in Forum V1 = I1 = N1 = 2 V2 I2 N2 1 
 ⇒ V1 = 2V2
 I 1 = 0.5 I2 
 In matrix form, V1  =  2 0   V2  I1 0 -0.5 I2 
 Correct Option: CV1 = I1 = N1 = 2 V2 I2 N2 1 
 ⇒ V1 = 2V2
 I 1 = 0.5 I2 
 In matrix form, V1  =  2 0   V2  I1 0 -0.5 I2 
 
 
	