Electric circuits miscellaneous


Electric circuits miscellaneous

  1. In the delta equivalent of the given star connected circuit, ZOR is equal to










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    ZQR =
    5 × 10 + 10 × j10 + j10 × 5
    = (10 + j30 ) Ω
    5

    Correct Option: D

    ZQR =
    5 × 10 + 10 × j10 + j10 × 5
    = (10 + j30 ) Ω
    5


  1. A delta connected network with Y-equivalent is shown below.

    The resistances R1, R2, R3 (in ohms) are respectively









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    R1 =
    Rab Rac
    =
    150
    = 3
    Rab + Rac + Rbc50

    R2 =
    Rab Rac
    =
    5 × 25
    = 1.5
    Rab + Rac + Rbc50

    R3 =
    30 × 15
    = 9
    50

    Correct Option: D

    R1 =
    Rab Rac
    =
    150
    = 3
    Rab + Rac + Rbc50

    R2 =
    Rab Rac
    =
    5 × 25
    = 1.5
    Rab + Rac + Rbc50

    R3 =
    30 × 15
    = 9
    50




  1. In the given figure, the switch was closed for a long time before opening at t = 0. The voltage Vx at t = 0+ is










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    At t = 0+ , the circuit will be as shown below.

    I L (0+) = 0
    Then Vi = – 50 V

    Correct Option: C

    At t = 0+ , the circuit will be as shown below.

    I L (0+) = 0
    Then Vi = – 50 V


  1. In a passive two-port network, the open-circuit impedance matrix is 102
    52

    If input port is interchanged with the output port, then open-circuit impedance matrix will be









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    The port-equations are
    V1 = 10 I 1 + 2I 2 ....(i)
    V2 = 2I 1 + 5 I2 ....(ii)
    Rewriting equations (i) and (ii) as
    V2 = 5 I2 + 2I1 ....(iii)
    V1 = 2 I2 + 10 I1 ....(iv)
    Writing in matrix form


    V2 = 52I2
    V1210I1

    Correct Option: B

    The port-equations are
    V1 = 10 I 1 + 2I 2 ....(i)
    V2 = 2I 1 + 5 I2 ....(ii)
    Rewriting equations (i) and (ii) as
    V2 = 5 I2 + 2I1 ....(iii)
    V1 = 2 I2 + 10 I1 ....(iv)
    Writing in matrix form


    V2 = 52I2
    V1210I1



  1. An ideal transformer has turns ratio of 2 : 1. Considering high voltage side as port 1 and low voltage side as port 2, then transmission line parameters of transformer will be









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    V1
    =
    I1
    =
    N1
    =
    2
    V2I2N21

    ⇒ V1 = 2V2
    I 1 = 0.5 I2

    In matrix form,

    V1 = 20V2
    I10-0.5I2

    Correct Option: C

    V1
    =
    I1
    =
    N1
    =
    2
    V2I2N21

    ⇒ V1 = 2V2
    I 1 = 0.5 I2

    In matrix form,

    V1 = 20V2
    I10-0.5I2