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In the circuit shown below, if the current through the resistor R is zero, what is the value of I?
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- 1 A
- 2 A
- 3 A
- 4A
- 1 A
Correct Option: D
When only voltage source
Using KVL in loop (1)
16 – 2 (i1 + i2) – 2i2 = 0
⇒ i1 + 2i2 = 8 ...(i)
Using KVL in loop (2)
16 – 2 (i1 + i2) – 4i1 = 0
3i1 + i2 = 8 ...(ii)
Solving equations (i) and (ii)
l2 = 2l1
Putting in equation (i)
i1 + 4i1 = 8
⇒ i1 = 1.6 Amp
When only current source
i1' = | = 0.4I Amp | |
2 + 3 |
Total current through R is zero.
Using superposition theorem
∴ i1 – i1' = 0
⇒ 1.6 – 0.4 I = 0
⇒ I = 4 Amp