Profit and Loss
- A man sells two chairs at $ 120 each and by doing so gains 25% on one chair and loses 25% on the other. His loss on the whole in $ is
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Given in question , SP of each chair = $ 120
On 25% gain ,C.P. of first chair = 100 × 120 = $ 96 125
On 25% loss ,C.P. of second chair = 100 × 120 = $ 160 75
Correct Option: B
Given in question , SP of each chair = $ 120
On 25% gain ,C.P. of first chair = 100 × 120 = $ 96 125
On 25% loss ,C.P. of second chair = 100 × 120 = $ 160 75
Total CP of chairs = 160 + 96 = $ 256
∴ Loss = Total CP - Total SP = 256 – 240 = $ 16
- A cloth merchant sold half of his cloth at 40% profit, half of remaining at 40% loss and the rest was sold at the cost price. In the total transaction, his gain or loss will be
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Let the merchant bought 100 metres of cloth for $ 100.
∴ Total S.P. = $ 
50 × 140 + 25 × 60 + 25 
100 6
Correct Option: C
Let the merchant bought 100 metres of cloth for $ 100.
∴ Total S.P. = $ 50 × 140 + 25 × 60 + 25 100 6
Total S.P. = $ (70 + 15 + 25) = $ 110
Gain = Total S.P. - Total C.P. = 110 - 100 = $ 10∴ Gain percent = 10 × 100 = 10% 100
- Two items A and B are sold at a profit of 10% and 15% respectively. If the amount of profit received is the same, then the cost price of A and B may be
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Check through option C ,
10% of 3000 = 3000 × 10 = $ 300 100
Correct Option: C
Check through option C ,
10% of 3000 = 3000 × 10 = $ 300 100 15% of 2000 = 2000 × 15 = $ 300 100
From above it is clear that required answer is option C , which is satisfied with the given condition in question .
- A shopkeeper sells an article at 15% gain. Had he sold it for $ 18 more, he would have gained 18%. The cost price (in $) of the article is
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Suppose C.P. of article be $ y
∴ (118 – 115)% of y = 18⇒ y × 3 = 18 100 ⇒ y = 18 × 100 = $ 600 3
We can find required answer with the help of given formula :
Here, a = 15%, R = 18, b = 18%C.P. = R × 100 b - a
Correct Option: C
Suppose C.P. of article be $ y
∴ (118 – 115)% of y = 18⇒ y × 3 = 18 100 ⇒ y = 18 × 100 = $ 600 3
We can find required answer with the help of given formula :
Here, a = 15%, R = 18, b = 18%C.P. = R × 100 b - a C.P. = 18 × 100 = $ 600 18 - 15
- A person bought two bicycles for $ 1600 and sold the first at 10% profit and the second at 20% profit. If he sold the first at 20% profit and the second at 10% profit, he would get $ 5 more. The difference of the cost price of the two bicycles was :
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Here , C.P. of two bicycles = $ 1600
If the C.P. of first bicycle be $ y, then C.P. of second bicycle = $ (1600 – y ). Then,
According to question ,y × 120 + (1600 - y) × 110 - y × 110 - (1600 - y) × 120 = 5 100 100 100 100
Correct Option: A
Here , C.P. of two bicycles = $ 1600
If the C.P. of first bicycle be $ y, then C.P. of second bicycle = $ (1600 – y ). Then,
According to question ,y × 120 + (1600 - y) × 110 - y × 110 - (1600 - y) × 120 = 5 100 100 100 100
⇒ 12y + 17600 – 11y – 11y – 19200 + 12y = 50
⇒ 2y = 50 + 19200 – 17600
⇒ 2y = 1650 ⇒ y = 825
C.P. of second cycle = 1600 – 825 = $ 775
Required Difference = 825 – 775 = $ 50
