Profit and Loss


  1. Nita blends two varieties of tea— one costing $ 180 per kg and another costing $ 200 per kg in the ratio 5 : 3. If she sells the blended variety at $ 210 per kg, then her gain percent is









  1. View Hint View Answer Discuss in Forum

    From the question , Total C.P. of two varieties of tea = 180 × 5 + 200 × 3 = $ 1500
    Total S.P. of two varieties of tea = 210 × (5 + 3) = 210 × 8 = $ 1680
    Gain = S.P. - C.P. = 1680 - 1500 = $ 180

    Gain percent =
    Gain
    × 100
    Total C.P. of two varieties of tea

    Correct Option: C

    From the question , Total C.P. of two varieties of tea = 180 × 5 + 200 × 3 = $ 1500
    Total S.P. of two varieties of tea = 210 × (5 + 3) = 210 × 8 = $ 1680
    Gain = S.P. - C.P. = 1680 - 1500 = $ 180

    Gain percent =
    Gain
    × 100
    Total C.P. of two varieties of tea

    Gain percent =
    180
    × 100
    1500

    Gain percent =
    180
    × 100 = 12%
    1500


  1. The prices of a refrigerator and a television set are in the ratio 5 : 3. If the refrigerator costs $ 5500 more than the television set, then the price of the refrigerator is:









  1. View Hint View Answer Discuss in Forum

    Given that , Ratio of prices of refrigerator and a television set = 5 : 3
    CP of refrigerator = $ 5k
    CP of television = $ 3k
    ∴ 2k = 5500

    ⇒ k =
    5500
    = 2750
    2

    Correct Option: C

    Given that , Ratio of prices of refrigerator and a television set = 5 : 3
    CP of refrigerator = $ 5k
    CP of television = $ 3k
    ∴ 2k = 5500

    ⇒ k =
    5500
    = 2750
    2

    ∴ CP of refrigerator = 5 × 2750 = $ 13750



  1. A milkman makes 20% profit by selling milk mixed with water at $ 9 per litre. If the cost price of 1 litre pure milk is $ 10, then the ratio of milk and water in the said mixture is









  1. View Hint View Answer Discuss in Forum

    Let Milk : Water = K : 1
    ∴ S.P. = (K + 1) × 9
    Cost price of 1 litre pure milk is $ 10 i.e.
    C.P. = 10K
    Gain = S.P. - C.P. = 9K + 9 - 10k = 9 – K

    Gain % =
    9 - K
    × 100
    10K

    Correct Option: A

    Let Milk : Water = K : 1
    ∴ S.P. = (K + 1) × 9
    Cost price of 1 litre pure milk is $ 10 i.e.
    C.P. = 10K
    Gain = S.P. - C.P. = 9K + 9 - 10k = 9 – K

    Gain % =
    9 - K
    × 100
    10K

    9 - K
    × 100 = 20
    10K

    ⇒ 90 – 10K = 20K
    ⇒ 30K = 90
    ⇒ K = 3
    ∴ Ratio = 3 : 1


  1. The cash difference between selling prices of an article at a profit of 4% and 6% is $ 3. The ratio of the two selling prices is









  1. View Hint View Answer Discuss in Forum

    Let the C.P. be y.
    ∴ (6 – 4)% of y = 3
    ⇒ 2% of y = 3

    ⇒ y =
    300
    = 150
    2

    ∴ S.P. at 4% gain =
    150 × 104
    = $ 156
    100

    Correct Option: B

    Let the C.P. be y.
    ∴ (6 – 4)% of y = 3
    ⇒ 2% of y = 3

    ⇒ y =
    300
    = 150
    2

    ∴ S.P. at 4% gain =
    150 × 104
    = $ 156
    100

    and S.P. at 6% gain =
    150 × 106
    = $ 159
    100

    ∴ The required ratio = 156 : 159 = 52 : 53



  1. The ratio of the C.P. and S.P. of an article is 20 : 21. What is the gain percent?









  1. View Hint View Answer Discuss in Forum

    Here , The ratio of the C.P. and S.P. of an article = 20 : 21
    Let the C.P. and S.P. of an article are 20k and 21k .
    Gain = 21k - 20k = k

    Gain% =
    k
    × 100
    20k

    Correct Option: A

    Here , The ratio of the C.P. and S.P. of an article = 20 : 21
    Let the C.P. and S.P. of an article are 20k and 21k .
    Gain = 21k - 20k = k

    Gain% =
    k
    × 100
    20k

    Gain% =
    1
    × 100 = 5%
    20