Profit and Loss
- A trader bought 10 kg of apples for $ 405 out of which 1 kg of apples were found to be rotten. If he wishes to make a profit of 10%, at what rate should he sell the remaining apples per kg?
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Here , CP of 10 kg of apples = $ 405
As per the given in question ,
Selling price = 405 × 110% = $ 445.50
If 1 kg of apples were found to be rotten.
Remaining apples = 10 – 1 = 9 kgCorrect Option: B
Here , CP of 10 kg of apples = $ 405
As per the given in question ,
Selling price = 405 × 110% = $ 445.50
If 1 kg of apples were found to be rotten.
Remaining apples = 10 – 1 = 9 kg
Therefore,the remaining apples (per kg) cost = 445.50 = $ 49.50 9
- Rahul buys a book for $ 400 and sells it for $ 500. The difference between his profit as a percentage of the buying price and then as a percentage of the selling price is
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Given that , CP of book = $ 400 and SP of book = $ 500
Profit = SP of book - SP of book = 500 - 400 = $ 100Profit percent at C.P. = Profit × 100 Cost Price Profit percent = 100 × 100 = 25% 400 Profit percent at S.P. = Profit × 100 S.P.
Correct Option: B
Given that , CP of book = $ 400 and SP of book = $ 500
Profit = SP of book - SP of book = 500 - 400 = $ 100Profit percent at C.P. = Profit × 100 Cost Price Profit percent = 100 × 100 = 25% 400 Profit percent at S.P. = Profit × 100 S.P. Profit percent at S.P. = 100 × 100 = 20% 500
∴ Required difference = Profit percent at S.P. - Profit percent at C.P.
∴ Required difference = 25 – 20 = 5%
- The difference between the selling prices of an article sold at 4% and 3% profits is Rs. 3. The cost price of the article is :
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Let the C.P. of article be Rs. y.
According to the question,
(104 – 103)% of y = 3
⇒ 1% × y = 3Correct Option: C
Let the C.P. of article be Rs. y.
According to the question,
(104 – 103)% of y = 3
⇒ 1% × y = 3⇒ y = 3 ⇒ y = Rs. 300 100
- If the difference between the selling prices of an article at profit of 6% and 4% is $ 3, then the cost price of the article should be :
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Suppose the cost price of article be y, then
Given in question ,
( 6 - 4 ) % of y = 3
⇒ 2% of y = 3⇒ y = 3 × 100 2
Correct Option: B
Suppose the cost price of article be y, then
Given in question ,
( 6 - 4 ) % of y = 3
⇒ 2% of y = 3⇒ y = 3 × 100 = $ 150 2
- The difference between the selling price and cost price of an article is $ 210. If the profit percent is 25, then the selling price of the article is
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Given in question , Selling price of an article - Cost price of an article = $ 210
Profit% = 25%Profit % = 25 = S.P. - C.P. × 100 C.P. ⇒ 210 × 100 = 25 C.P. ⇒ C.P. = 100 × 210 = 840 25 ∴ S.P. = 125 of 840 100
Correct Option: B
Given in question , Selling price of an article - Cost price of an article = $ 210
Profit% = 25%Profit % = 25 = S.P. - C.P. × 100 C.P. ⇒ 210 × 100 = 25 C.P. ⇒ C.P. = 100 × 210 = 840 25 ∴ S.P. = 125 of 840 100 S.P. = 840 × 125 = $ 1050 100