Profit and Loss
- The ratio of cost price and selling price is 5 : 4, the loss percent is :
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Here , cost price : selling price = 5 : 4
According to the questionCost price = 5 Selling price 4 ∴ Selling price = 4 × Cost price 5
Loss = Cost price – Selling priceLoss = Cost price – 4 Cost price 5 Loss = 1 Cost price 5 ∴ Loss % = (1 / 5) cost price × 100 = 100 = 20% cost price 5
Second method to solve this question :
$ 1 is loss on $ 5.
Correct Option: A
Here , cost price : selling price = 5 : 4
According to the questionCost price = 5 Selling price 4 ∴ Selling price = 4 × Cost price 5
Loss = Cost price – Selling priceLoss = Cost price – 4 Cost price 5 Loss = 1 Cost price 5 ∴ Loss % = (1 / 5) cost price × 100 = 100 = 20% cost price 5
Second method to solve this question :
$ 1 is loss on $ 5.∴ loss % = 1 × 100 = 20% 5
We can find required answer with the help of given formula :
Here, C.P. = 5k, S.P. = 4kloss % = Loss × 100 C.P. loss % = 5k - 4k × 100 = 20% 5k
- A man sells an article at 15% profit. If he had sold it for Rs. 6 more, he would have gained 18%. The man bought the article for
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Let the C.P. of article be Rs. y.
According to the question ,
(118 – 115)% of y = 6⇒ y × 3 = 6 100
Correct Option: C
Let the C.P. of article be Rs. y.
According to the question ,
(118 – 115)% of y = 6⇒ y × 3 = 6 100 ⇒ y = 600 = Rs. 200 3
- A man bought 25 crates of oranges for Rs. 10,000. He lost 5 crates. In order to earn a total profit of 25% of the total cost, he would have to sell each of the remaining crates at
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Given in question , Five crates out of 25 crates of oranges were lost.
∴ C.P. of 20 crates of oranges = Rs. 10000S.P. of 20 crates of oranges = Rs. 10000 × 125 = Rs. 12500 100
Correct Option: B
Given in question , Five crates out of 25 crates of oranges were lost.
∴ C.P. of 20 crates of oranges = Rs. 10000S.P. of 20 crates of oranges = Rs. 10000 × 125 = Rs. 12500 100 ∴ S.P. per crate = 12500 = Rs. 625 20
- Kamal has some apples. He sold 40% more than he ate. If he sold 70 apples, how many did he eat?
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Let Kamal eat y apples.
According to the question,y × 140 = 70 ⇒ 14y = 70 100 10
Correct Option: C
Let Kamal eat y apples.
According to the question,y × 140 = 70 ⇒ 14y = 70 100 10 ⇒ y = 70 × 10 = 50 14
- A man bought 30 defective machines for Rs. 1000. He repaired and sold them at the rate of Rs. 300 per machine. He got profit of Rs. 150 per machine. How much did he spend on repairs? (in Rupees)
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Given that , C.P. of 30 defective machines = Rs. 1000.
Let total expenditure on repairing be Rs. y.
∴ Actual C.P. = Rs. (1000 + y)
S.P. of 1 defective machine = Rs. 300
∴ Total S.P. of 30 defective machines = Rs. (300 × 30) = Rs. 9000
Total profit = Rs. (150 × 30) = Rs. 4500Correct Option: C
Given that , C.P. of 30 defective machines = Rs. 1000.
Let total expenditure on repairing be Rs. y.
∴ Actual C.P. = Rs. (1000 + y)
S.P. of 1 defective machine = Rs. 300
∴ Total S.P. of 30 defective machines = Rs. (300 × 30) = Rs. 9000
Total profit = Rs. (150 × 30) = Rs. 4500
∴ 9000 – (1000 + y) = 4500
⇒ 1000 + y = 9000 – 4500 = 4500
⇒ y = 4500 – 1000 = Rs. 3500