Profit and Loss
- A shop-keeper sold a sewing machine for $ 1,080 at a loss of 10%. At what price should he has to sold it so as to gain 10% on it ? (in $ )
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Here , Selling Price of sewing machine = $ 1080
at a loss of 10% ,Cost price of sewing machine = 1080 × 100 = $1200 90
Correct Option: D
Here , Selling Price of sewing machine = $ 1080
at a loss of 10% ,Cost price of sewing machine = 1080 × 100 = $1200 90 ∴ S.P. for a profit of 10% = 1200 × 110 = $1320 100
- A fruit-seller buys some oranges and by selling 40% of them he realises the cost price of all the oranges. As the oranges being to grow over-ripe, he reduces the price and sells 80% of the remaining oranges at half the previous rate of profit. The rest of the oranges being rotten are thrown away. The overall percentage of profit is
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Let Number of oranges bought = 100
And C.P. of oranges = $ 100
S.P of 40 oranges = $ 100
Gain on 40 Oranges = 100 - 40 = $ 60∴ Gain percent = 60 × 100 = 150 % 40
Remaining oranges = 60Their 80 % = 60 × 80 = 48 100
Correct Option: B
Let Number of oranges bought = 100
And C.P. of oranges = $ 100
S.P of 40 oranges = $ 100
Gain on 40 Oranges = 100 - 40 = $ 60∴ Gain percent = 60 × 100 = 150 % 40
Remaining oranges = 60Their 80 % = 60 × 80 = 48 100
These are sold at a profit of 75 % .∴ Their S.P. = 48 × 175 = $ 84 100
12 oranges was rotten so he threw away.
∴ Total SP = 100 + 84 = $ 184
Gain = Total SP - CP = 184 - 100 = $ 84∴ Gain percent = 84 × 100 = 84% 100
- An item costing $ 200 is being sold at 10% loss. If the price is further reduced by 5%, the selling price will be
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Given , Cost Price = $ 200 ,
For 10% loss ,First S.P. of article
=200 × 90 = $ 180 100
After decrease of 5%,
Correct Option: B
Given , Cost Price = $ 200 ,
For 10% loss ,First S.P. of article
=200 × 90 = $ 180 100
After decrease of 5%,S.P. = 180 × 95 = $ 171 100
- By selling an article for $ 102, there is a loss of 15%, when the article is sold for $ 134.40, the net result in the transaction is
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Given in question , Selling Price of article = $ 102 and Loss = 15%
C.P. of article = 100 × S.P. 100 – loss percent C.P. of article = 100 × 102 = $ 120 100 – 15
On selling at Rs. 134.40,
Gain = $ (134.4 – 120) = $ 14.4
Correct Option: A
Given in question , Selling Price of article = $ 102 and Loss = 15%
C.P. of article = 100 × S.P. 100 – loss percent C.P. of article = 100 × 102 = $ 120 100 – 15
On selling at Rs. 134.40,
Gain = $ (134.4 – 120) = $ 14.4∴ Gain percent = 14.4 × 100 = 12% 120
- Two toys are sold at $ 504 each. One toy brings the dealer a gain of 12% and the other a loss of 4%. The gain or loss percent by selling both the toys is
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Let C.P. of first toy = $ p
C.P. of second toy = $ q∴ p × 112 = 504 100 ⇒ p = 504 × 100 = $ 450 112 Again, q × 96 = 504 100 ⇒ q = 504 × 100 = $ 525 96
Total C.P. = $ (450 + 525) = $ 975
Total S.P. = 2 × 504 = $ 1008
Gain = Total S.P. - Total C.P. = 1008 – 975 = $ 33
Correct Option: A
Let C.P. of first toy = $ p
C.P. of second toy = $ q∴ p × 112 = 504 100 ⇒ p = 504 × 100 = $ 450 112 Again, q × 96 = 504 100 ⇒ q = 504 × 100 = $ 525 96
Total C.P. = $ (450 + 525) = $ 975
Total S.P. = 2 × 504 = $ 1008
Gain = Total S.P. - Total C.P. = 1008 – 975 = $ 33∴ Profit percent = 33 × 100 975 Profit percent = 44 = 3 5 % 13 13