Profit and Loss
- If the cost price of 10 articles is equal to the selling price of 16 articles, then the loss percent is
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Let C.P. of each article = $ 1
Then , C.P. of 16 articles = $ 16
S.P. of 16 articles = $ 10
Loss = C.P. of 16 articles - S.P. of 16 articles = 16 - 10 = $ 6Loss percent = Loss × 100 C.P. of 16 articles Loss percent = 6 × 100 = 37.5% 16
Second method to solve this question :
Here, p = 10, q = 16Loss % = q - p × 100 q
Correct Option: B
Let C.P. of each article = $ 1
Then , C.P. of 16 articles = $ 16
S.P. of 16 articles = $ 10
Loss = C.P. of 16 articles - S.P. of 16 articles = 16 - 10 = $ 6Loss percent = Loss × 100 C.P. of 16 articles Loss percent = 6 × 100 = 37.5% 16
Second method to solve this question :
Here, p = 10, q = 16Loss % = q - p × 100 q Loss % = 16 - 10 × 100 16 Loss % = 600 = 37.5% 16
- If the selling price of 4 articles is equal to the cost price of 5 articles, the profit per cent is
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If the CP of each article be $ 1 then
CP of 4 articles = $ 4
SP of 4 articles = $ 5
Profit = SP of 4 articles - CP of 4 articles = 5 - 4 = $ 1∴ Profit percent = Profit × 100 % CP of 4 articles Profit percent = 1 × 100 = 25% 4
Second method to solve this question :
Here, p = 5, q = 4Profit % = p - q × 100 q
Correct Option: C
If the CP of each article be $ 1 then
CP of 4 articles = $ 4
SP of 4 articles = $ 5
Profit = SP of 4 articles - CP of 4 articles = 5 - 4 = $ 1∴ Profit percent = Profit × 100 % CP of 4 articles Profit percent = 1 × 100 = 25% 4
Second method to solve this question :
Here, p = 5, q = 4Profit % = p - q × 100 q Profit % = 5 - 4 × 100 4 Profit % = 100 = 25% 4
- The selling price of 10 oranges is the cost price of 13 oranges. Then the profit percentage is
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Let the CP of 1 orange = $ 1
then , CP of 10 oranges = $ 10
∴ SP of 10 oranges = $ 13
Gain = SP of 10 oranges - CP of 10 oranges = 13 - 10 = $ 3∴ Gain percent = Gain × 100 CP of 10 oranges Gain percent = 3 × 100 = 30 % 10
Second method to solve this question :
Here, p = 13, q = 10Profit % = p - q × 100 q
Correct Option: A
Let the CP of 1 orange = $ 1
then , CP of 10 oranges = $ 10
∴ SP of 10 oranges = $ 13
Gain = SP of 10 oranges - CP of 10 oranges = 13 - 10 = $ 3∴ Gain percent = Gain × 100 CP of 10 oranges Gain percent = 3 × 100 = 30 % 10
Second method to solve this question :
Here, p = 13, q = 10Profit % = p - q × 100 q Profit % = 13 - 10 × 100 10 Profit % = 300 = 30% 10
- If the selling price of 10 articles is equal to the cost price of 11 articles, then the gain percent is
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Let the C.P. of each article be $ 1.
∴ C.P. of 10 articles = $ 10
and S.P. of 10 articles = $ 11
Profit = S.P. of 10 articles - C.P. of 10 articles = 11 - 10 = $ 1∴ Profit percent = Profit × 100 C.P. of 10 articles Profit percent = 1 × 100 = 10% 10
Second method to solve this question :
Here, p = 11, q = 10Profit % = p - q × 100 q
Correct Option: A
Let the C.P. of each article be $ 1.
∴ C.P. of 10 articles = $ 10
and S.P. of 10 articles = $ 11
Profit = S.P. of 10 articles - C.P. of 10 articles = 11 - 10 = $ 1∴ Profit percent = Profit × 100 C.P. of 10 articles Profit percent = 1 × 100 = 10% 10
Second method to solve this question :
Here, p = 11, q = 10Profit % = p - q × 100 q Profit % = 11 - 10 × 100 10 = 100 = 10% 10
- If the cost price of 10 articles is equal to the selling price of 8 articles, then gain per cent is
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Let the C.P. of each article be 1.
∴ C.P. of 8 articles = $ 8
and S.P. of 8 articles = $ 10
Profit = S.P. of 8 articles - C.P. of 8 articles = 10 - 8 = $ 2Profit percent = Profit × 100 C.P. of 8 articles Profit percent = 2 × 100 = 25% 8
Second method to solve this question :
Here, p = 10, q = 8Gain % = p - q × 100 q
Correct Option: D
Let the C.P. of each article be 1.
∴ C.P. of 8 articles = $ 8
and S.P. of 8 articles = $ 10
Profit = S.P. of 8 articles - C.P. of 8 articles = 10 - 8 = $ 2Profit percent = Profit × 100 C.P. of 8 articles Profit percent = 2 × 100 = 25% 8
Second method to solve this question :
Here, p = 10, q = 8Gain % = p - q × 100 q Gain % = 10 - 8 × 100 8 Gain % = 200 = 25% 8