Profit and Loss
- A sold a horse to B for 4800 by losing 20%. B sells it to C at a price which would have given A a profit of 15%. B’s gain is
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Here , A sold a horse to B for 4800 by losing 20% .
For A,C.P. of horse = 4800 × 100 = $ 6000 80
For B,S.P. of horse = 6000 × 115 = $ 6900 100
Correct Option: D
Here , A sold a horse to B for 4800 by losing 20% .
For A,C.P. of horse = 4800 × 100 = $ 6000 80
For B,S.P. of horse = 6000 × 115 = $ 6900 100
B’s profit = Rs. (6900 – 4800) = $ 2100
- A fruit vendor buys apples at the rate of 10 for 100. How many should he sell for 100, so that he makes a profit of 25 %?
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Given in question , C.P. of 10 apples = $ 100
∴ C.P. of each apple = 100 = $ 10 10 S.P. of each apple = $ 
10 × 125 
= $ 12.50 100
Correct Option: D
Given in question , C.P. of 10 apples = $ 100
∴ C.P. of each apple = 100 = $ 10 10 S.P. of each apple = $ 10 × 125 = $ 12.50 100 ∴ Number of apples sold for Rs. 100 = 100 S.P. of each apple Number of apples sold for Rs. 100 = 100 = 8 12.5
- A table is sold at a profit of 13%. If it is sold for $ 25 more, profit is 18 %. Cost price of table is
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Let Cost price of table = $ y
We know that ,S. P. at R% profit = (100 + R) × C.P. 100
According to question,∴ 113y + 25 = 118y % 100 100 ⇒ 118y - 113y = 25 100 100 ⇒ 5y = 25 ⇒ y = 25 100 20
⇒ y = 25 × 20 = $ 500
We can find required answer with the help of given formula :
Here, a = 13%, and R = $ 25, b = 18%C.P. of table = R × 100 b - a
Correct Option: B
Let Cost price of table = $ y
We know that ,S. P. at R% profit = (100 + R) × C.P. 100
According to question,∴ 113y + 25 = 118y % 100 100 ⇒ 118y - 113y = 25 100 100 ⇒ 5y = 25 ⇒ y = 25 100 20
⇒ y = 25 × 20 = $ 500
We can find required answer with the help of given formula :
Here, a = 13%, and R = $ 25, b = 18%C.P. of table = R × 100 b - a C.P. of table = 25 × 100 18 - 13 C.P. of table = 25 × 100 = $ 500 5
- A man sold his watch at a loss of 5%. Had he sold it for $ 56.25 more, he would have gained 10%. What is the cost price of the watch (in $)?
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Let C.P. of watch = $ y
∴ S.P. of watch = y × 95 100 S.P. of watch = $ 19y 20
Case II,S.P. = $ 19y + 56.25 20
Profit percent = 10 %∴ y × 110 = 19y + 56.25 100 20 ⇒ 11y - 19y = 56.25 10 20 ⇒ 22y - 19y = 56.25 20 ⇒ 3y = 56.25 20
⇒ 3y = 56.25 × 20⇒ y = 56.25 × 20 = $ 375 3
We can find required answer with the help of given formula :
Here, a = 5%, and R = $ 56.25, b = 10%C.P. = R × 100 a + b
Correct Option: C
Let C.P. of watch = $ y
∴ S.P. of watch = y × 95 100 S.P. of watch = $ 19y 20
Case II,S.P. = $ 19y + 56.25 20
Profit percent = 10 %∴ y × 110 = 19y + 56.25 100 20 ⇒ 11y - 19y = 56.25 10 20 ⇒ 22y - 19y = 56.25 20 ⇒ 3y = 56.25 20
⇒ 3y = 56.25 × 20⇒ y = 56.25 × 20 = $ 375 3
We can find required answer with the help of given formula :
Here, a = 5%, and R = $ 56.25, b = 10%C.P. = R × 100 a + b C.P. = 56.25 × 100 10 + 5 C.P. = 56.25 × 100 15 C.P. = 5625 = $ 375 15
- Kamala bought a bicycle for $ 1,650. She had to sell it at a loss of 8%. She sold it for
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Here , C.P. of cycle = $ 1650 and Loss = 8%
∴ S.P. of cycle = 100 - loss% × C.P. 100
Correct Option: B
Here , C.P. of cycle = $ 1650 and Loss = 8%
∴ S.P. of cycle = 100 - loss% × C.P. 100 S.P. of cycle = 100 - 8 × 1650 100 S.P. of cycle = 92 × 1650 = $ 1518 100
