Profit and Loss
- The cost price of 8 articles is equal to the selling price of 9 articles. The profit or loss percent in the transaction is
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Let the CP of each article be $ 1
∴ CP of 9 articles = $ 9
∴ SP of 9 articles = $ 8
∴ Loss = 9 - 8 = $ 1∴ Loss % = 1 × 100 9 Loss % = 100 = 11 1 % 9 9
Second method to solve this question :
Here, p = 8, q = 9Loss % = q - p × 100 q
Correct Option: C
Let the CP of each article be $ 1
∴ CP of 9 articles = $ 9
∴ SP of 9 articles = $ 8
∴ Loss = 9 - 8 = $ 1∴ Loss % = 1 × 100 9 Loss % = 100 = 11 1 % 9 9
Second method to solve this question :
Here, p = 8, q = 9Loss % = q - p × 100 q Loss % = 9 - 8 × 100 9 Loss % = 100 = 11 1 % 9 9
- If the cost price of 12 pens is equal to the selling price of 8 pens, the gain percent is :
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View Hint View Answer Discuss in Forum
Let the CP of each pen be $ 1.
∴ CP of 8 pens = $ 8
SP of 8 pens = $ 12∴ Gain % = 4 × 100 = 50% 8
Second method to solve this question :
Here, p = 12, q = 8Profit % = p - q × 100 q
Correct Option: D
Let the CP of each pen be $ 1.
∴ CP of 8 pens = $ 8
SP of 8 pens = $ 12∴ Gain % = 4 × 100 = 50% 8
Second method to solve this question :
Here, p = 12, q = 8Profit % = p - q × 100 q Profit % = 12 - 8 × 100 8 Profit % = 4 × 100 = 50% 8
- A man sells 320 mangoes at the cost price of 400 mangoes. His gain percent is :
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Let Cost price of each mango is Rs. 1.
Given in question , Selling price of 320 mangoes = Cost price of 400 mangoes⇒ Cost price of mangoes = 320 Selling price of mangoes 400
Gain = S.P. - C.P. = 400 - 320 = Rs. 80Gain percent = Gain × 100 Cost price Gain percent = 80 × 100 = 25% 320
Second method to solve this question :
Here, p = 400, q = 320Profit % = p - q × 100 q
Correct Option: C
Let Cost price of each mango is Rs. 1.
Given in question , Selling price of 320 mangoes = Cost price of 400 mangoes⇒ Cost price of mangoes = 320 Selling price of mangoes 400
Gain = S.P. - C.P. = 400 - 320 = Rs. 80Gain percent = Gain × 100 Cost price Gain percent = 80 × 100 = 25% 320
Second method to solve this question :
Here, p = 400, q = 320Profit % = p - q × 100 q Profit % = 400 - 320 × 100 320 Profit % = 80 × 100 = 25% 320
- If the cost price of 10 articles is equal to the selling price of 9 articles, the gain or loss percent is
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View Hint View Answer Discuss in Forum
Let C.P. of each article be $ 1
Then, C.P. of 9 articles = $ 9
S.P. of 9 articles = $ 10
Profit = S.P. of 9 articles - C.P. of 9 articles = 10 - 9 = $ 1Required profit percent = Profit × 100 C.P. of 9 articles Required profit percent = 1 × 100 = 11 1 % 9 9
Second method to solve this question :
Here, p = 10, q = 9Profit % = p - q × 100 q
Correct Option: A
Let C.P. of each article be $ 1
Then, C.P. of 9 articles = $ 9
S.P. of 9 articles = $ 10
Profit = S.P. of 9 articles - C.P. of 9 articles = 10 - 9 = $ 1Required profit percent = Profit × 100 C.P. of 9 articles Required profit percent = 1 × 100 = 11 1 % 9 9
Second method to solve this question :
Here, p = 10, q = 9Profit % = p - q × 100 q Profit % = 10 - 9 × 100 9 Profit % = 1 × 100 9 = 11 1 % 9
- If the cost price of 12 oranges is equal to selling price of 10 oranges, then the percentage of profit is
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View Hint View Answer Discuss in Forum
Let C.P. of each orange be $ 1
Then, C.P. of 10 oranges = $ 10
S.P. of 10 oranges = $ 12
Gain = 12 - 10 = $ 2∴ Gain % = Gain × 100 C.P. of 10 oranges Gain % = 2 × 100 % = 20% 10
Second method to solve this question :
Here, p = 12, q = 10Profit % = p - q × 100 q
Correct Option: B
Let C.P. of each orange be $ 1
Then, C.P. of 10 oranges = $ 10
S.P. of 10 oranges = $ 12
Gain = 12 - 10 = $ 2∴ Gain % = Gain × 100 C.P. of 10 oranges Gain % = 2 × 100 % = 20% 10
Second method to solve this question :
Here, p = 12, q = 10Profit % = p - q × 100 q Profit % = 12 - 10 × 100 = 20% 10