Profit and Loss


  1. Yogita sold a plasma TV at 20% gain to Shyamla. Shyamla sold it to Deepa at 10% profit. If Deepa had to pay $ 33,000 for the plasma TV, find the cost price of the plasma TV for Yogita.









  1. View Hint View Answer Discuss in Forum

    Let C.P. of T.V. for Yogita = $ y
    According to question,

    y ×
    120
    ×
    110
    = 33000
    100100

    ⇒ y =
    33000 × 100 × 100
    = $ 25000
    120 × 110

    We can find required answer with the help of given formula :
    Here, r1 = 20%, r2 = 10%
    C.P. for Deepa = C.P. for yogita

    33000 = C.P. for Yogita

    Correct Option: B

    Let C.P. of T.V. for Yogita = $ y
    According to question,

    y ×
    120
    ×
    110
    = 33000
    100100

    ⇒ y =
    33000 × 100 × 100
    = $ 25000
    120 × 110

    We can find required answer with the help of given formula :
    Here, r1 = 20%, r2 = 10%
    C.P. for Deepa = C.P. for yogita

    33000 = C.P. for Yogita

    C.P. for Yogita =
    33000 × 100 × 100
    = $ 25000
    120 × 110


  1. A sells a cycle to B at a profit of 20% and B sells it to C at a loss of 25%. If C bought the cycle for $ P, then the cost price of it for A was









  1. View Hint View Answer Discuss in Forum

    Suppose C.P. for A = Rs. y
    According to the question,

    y × 120
    ×
    75
    = P
    100100

    ⇒ y =
    P × 100 × 100
    120 × 75

    = Rs.
    10
    9

    We can find required answer with the help of given formula :
    Here, r1 = 20%, r2 = 25% (Loss)
    C.P. for C = C.P. for A

    P = C.P. for A

    Correct Option: D

    Suppose C.P. for A = Rs. y
    According to the question,

    y × 120
    ×
    75
    = P
    100100

    ⇒ y =
    P × 100 × 100
    120 × 75

    = Rs.
    10
    9

    We can find required answer with the help of given formula :
    Here, r1 = 20%, r2 = 25% (Loss)
    C.P. for C = C.P. for A

    P = C.P. for A

    C.P. for A =
    P × 100 × 100
    120 × 75

    C.P. for A =
    10P
    9



  1. The profit obtained by selling an article for Rs. 625 is same as the loss incurred if it is sold for Rs. 545. The price at which it is to be sold to realize a profit of Rs. 65 on the cost price is









  1. View Hint View Answer Discuss in Forum

    Given in question , S.P. of article be Rs. 545.
    Let C.P. of article be Rs. y.
    According of the question,
    625 – y = y – 545
    ⇒ 2y= 625 + 545 = 1170

    ⇒ y =
    1170
    = Rs. 585
    2

    Correct Option: C

    Given in question , S.P. of article be Rs. 545.
    Let C.P. of article be Rs. y.
    According of the question,
    625 – y = y – 545
    ⇒ 2y= 625 + 545 = 1170

    ⇒ y =
    1170
    = Rs. 585
    2

    ∴ Required S.P. = Rs. (585 + 65) = Rs. 650


  1. There would be a 10% loss, if rice is sold at Rs. 54 per kg. To earn a profit of 20%, the price of rice per kg will be









  1. View Hint View Answer Discuss in Forum

    Here , S.P. of rice per kg = Rs. 54

    ∴ C.P. of rice per kg =
    54 × 100
    = Rs. 60
    90

    For 20% profit,
    S.P. per kg. =
    60 × 120
    = Rs. 72
    100

    Using the given formula :
    Here , Loss% = 10%
    C.P. = S.P.100
    100 - Loss%

    C.P. = 54100
    100 - 10

    C.P. = Rs. 60
    New S.P. = C.P.100 + Profit%
    100

    Correct Option: D

    Here , S.P. of rice per kg = Rs. 54

    ∴ C.P. of rice per kg =
    54 × 100
    = Rs. 60
    90

    For 20% profit,
    S.P. per kg. =
    60 × 120
    = Rs. 72
    100

    Using the given formula :
    Here , Loss% = 10%
    C.P. = S.P.100
    100 - Loss%

    C.P. = 54100
    100 - 10

    C.P. = Rs. 60
    New S.P. = C.P.100 + Profit%
    100

    New S.P. = 60 ×100 + 20 = $ 72
    100



  1. A merchant has 1000 kg sugar, part of which sells at 8% profit and the rest at 18% profit. He gain 14% on the whole. The quantity sold at 8% profit is :









  1. View Hint View Answer Discuss in Forum

    Let the quantity of sugar at 8% profit be y kg.
    ∴ Quantity of sugar sold at 18% = (100 – y) kg
    According to the question,

    y ×
    108
    + (1000 - y) ×
    118
    =
    1000 × 114
    100100100

    Correct Option: D

    Let the quantity of sugar at 8% profit be y kg.
    ∴ Quantity of sugar sold at 18% = (100 – y) kg
    According to the question,

    y ×
    108
    + (1000 - y) ×
    118
    =
    1000 × 114
    100100100

    ⇒ 108y + 118000 – 118y = 114000
    ⇒ 118y - 108y = 118000 – 114000
    ⇒ 10y = 4000 ⇒ y = 400 kg