Profit and Loss


  1. A shopkeeper blends two varieties of tea costing $ 18 and $ 13 per 100 gm in the ratio 7 : 3. He sells the blended variety at the rate of $ 18.15 per 100 gm. His percentage gain in the transaction is









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    Here , Ratio of two varieties of tea = 7 : 3
    As per the given in question ,
    C.P. of 700 gm of tea at $ 18 per 100 gm = 7 × 18 = $ 126
    C.P. of 300 gm of tea at $ 13 per 100 gm = 3 × 13 = $ 39
    Total cost of 1000 gm = 126 + 39 = $ 165
    Total S.P. of 1000 gm = 18.15 × 10= $ 181.5
    Gain = Total S.P. of 1000 gm - Total C.P. of 1000 gm

    Correct Option: A

    Here , Ratio of two varieties of tea = 7 : 3
    As per the given in question ,
    C.P. of 700 gm of tea at $ 18 per 100 gm = 7 × 18 = $ 126
    C.P. of 300 gm of tea at $ 13 per 100 gm = 3 × 13 = $ 39
    Total cost of 1000 gm = 126 + 39 = $ 165
    Total S.P. of 1000 gm = 18.15 × 10= $ 181.5
    Gain = Total S.P. of 1000 gm - Total C.P. of 1000 gm
    Gain = 181.5 – 165 = $ 16.5

    Gain percent =
    16.5
    × 100 = 10%
    165


  1. A fruit seller buys some apples at the rate of 4 for $ 10 and an equal number more at 5 for $ 10. He sells the whole lot at 9 for $ 20. What is his loss or gain percent?









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    ∵ LCM of 4 and 5 = 20
    Let 20 apples of each type be bought.
    C.P. at the rate of 4 apples = $ 10

    C.P. of an apple of first type = $
    10
    4

    C.P. at the rate of 5 apples = $ 10
    C.P. of an apple of second type = $
    10
    5

    C.P. of 40 apples = $20 ×10 + 20 ×10 = $ 90
    45

    Total S.P. =
    40 × 20
    = $
    800
    99

    Correct Option: A

    ∵ LCM of 4 and 5 = 20
    Let 20 apples of each type be bought.
    C.P. at the rate of 4 apples = $ 10

    C.P. of an apple of first type = $
    10
    4

    C.P. at the rate of 5 apples = $ 10
    C.P. of an apple of second type = $
    10
    5

    C.P. of 40 apples = $20 ×10 + 20 ×10 = $ 90
    45

    Total S.P. =
    40 × 20
    = $
    800
    99

    Loss = C.P. of 40 apples - S.P. of 40 apples
    Loss = 90 -
    800
    =
    10
    99


    Loss percent =
    100
    = 1
    19
    %
    8181



  1. Some toffees were bought at the rate of 11 for $ 10 and the same number at the rate of 9 for $ 10. If the whole lot was sold at one rupee per toffee, then the gain or loss in the whole transaction was









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    For the sake of convenience, Let the number of toffees of each type bought be 99 (LCM of 11 and 9 = 99 ).
    CP of first kind of 99 toffees = $ 90
    CP of second kind of 99 toffees = $ 110
    ∴ CP of 198 toffees = $ 200
    ∴ SP of 198 toffees = $ 198
    Loss = 200 - 198 = $ 2

    Correct Option: A

    For the sake of convenience, Let the number of toffees of each type bought be 99 (LCM of 11 and 9 = 99 ).
    CP of first kind of 99 toffees = $ 90
    CP of second kind of 99 toffees = $ 110
    ∴ CP of 198 toffees = $ 200
    ∴ SP of 198 toffees = $ 198
    Loss = 200 - 198 = $ 2

    Loss % =
    2
    × 100 = 1%
    200


  1. A shopkeeper purchased a TV for $ 2,000 and a radio for $ 750. He sells the TV at a profit of 20% and the radio at a loss of 5%. The total loss or gain is









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    Given , C.P. of TV = $ 2000

    ∴ S.P. of TV = 2000 ×
    120
    = $ 2400
    100

    C.P. of radio = $ 750
    ∴ S.P. of radio =
    750 × 95
    = $ 712.5
    100

    Correct Option: B

    Given , C.P. of TV = $ 2000

    ∴ S.P. of TV = 2000 ×
    120
    = $ 2400
    100

    C.P. of radio = $ 750
    ∴ S.P. of radio =
    750 × 95
    = $ 712.5
    100

    Total S.P. = 2400 + 712.5 = $ 3112.50
    Total C.P. = 2000 + 750 = $ 2750
    ∴ Gain = Total S.P. - Total C.P. = 3112.5 – 2750 = $ 362.50



  1. A man purchases two fans for $ 2,160. By selling one fan at a profit of 15% and the other at a loss of 9% he neither gains nor loses in the whole transaction. Find the cost price of each fan in $.









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    Let the C.P. of fans be $ p and $ q respectively.
    As per the given in question,

    p × 15
    =
    q × 9
    100100

    p
    =
    9
    =
    3

    q155

    Sum of ratios = 3 + 5 = 8
    C.P. of first fan =
    3
    × 2160 = $ 810
    8

    Correct Option: C

    Let the C.P. of fans be $ p and $ q respectively.
    As per the given in question,

    p × 15
    =
    q × 9
    100100

    p
    =
    9
    =
    3

    q155

    Sum of ratios = 3 + 5 = 8
    C.P. of first fan =
    3
    × 2160 = $ 810
    8

    & C.P. of second fan =
    5
    × 2160 = $ 1350
    8