Profit and Loss
- The printed price of an article is 40% higher than its cost price. Then the rate of discount such that he gains 12% profit is
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Suppose C.P of article = Rs. 100
∴ Marked price = Rs. 140
At 12% gain, S.P. = Rs. 112
∴ Discount = Marked price - S.P. of article
∴ Discount = 140 – 112 = Rs. 28
If the rate of discount be y%, then
140 × y% = 28⇒ 140 × y = 28 100
Correct Option: D
Suppose C.P of article = Rs. 100
∴ Marked price = Rs. 140
At 12% gain, S.P. = Rs. 112
∴ Discount = Marked price - S.P. of article
∴ Discount = 140 – 112 = Rs. 28
If the rate of discount be y%, then
140 × y% = 28⇒ 140 × y = 28 100 ⇒ y = 28 × 100 = 20% 140
- A shopkeeper bought 30 kg of rice at the rate of Rs. 70 per kg and 20 kg of rice at the rate of Rs. 70.75 per kg. If he mixed the two brands of rice and sold the mixture at Rs. 80.50 per kg, his gain is
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As per the given in question ,
C.P. of 50 kg of rice = Rs. (30 × 70 + 20 × 70.75)
C.P. of 50 kg of rice = Rs. (2100 + 1415) = Rs. 3515
S.P. of 50 kg. of rice = Rs. (50 × 80.50) = Rs. 4025
∴ Profit = S.P. of 50 kg. of rice - C.P. of 50 kg. of riceCorrect Option: B
As per the given in question ,
C.P. of 50 kg of rice = Rs. (30 × 70 + 20 × 70.75)
C.P. of 50 kg of rice = Rs. (2100 + 1415) = Rs. 3515
S.P. of 50 kg. of rice = Rs. (50 × 80.50) = Rs. 4025
∴ Profit = S.P. of 50 kg. of rice - C.P. of 50 kg. of rice
Profit = Rs. (4025 – 3515) = Rs. 510
- If the cost price of an item is (5 / 9) of its marked price and the profit is 20%, then the percentage of discount is
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Let Marked price of article = Rs. p
∴ C.P. of article = Rs. 5p 9
If the rate of discount be q %, then
From the question ,∴ p × (100 – q)% = 120 % of 5p 9 ⇒ 100 – q = 5 × 120 9
Correct Option: C
Let Marked price of article = Rs. p
∴ C.P. of article = Rs. 5p 9
If the rate of discount be q %, then
From the question ,∴ p × (100 – q)% = 120 % of 5p 9 ⇒ 100 – q = 5 × 120 9
⇒ 300 – 3q = 200
⇒ 3q = 300 – 200 = 100⇒ q = 100 = 33 1 % 3 3
- Rohit sold his car at 10% below the cost price to Amit. Amit got the car repaired and spent Rs. 5,000. He then sold the car to Rajesh at 20% above the total cost, which is equal to Rs. 1,00,000. Find the original price of the car (nearest to hundred).
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Suppose Original price of car = Rs. y
C.P. of car for Amit = 90 × y = Rs. 9y 100 10 Actual C.P. = Rs. 9y + 5000 10
According to the question,9y + 5000 × 120 = 100000 10 100 ⇒ 9y + 5000 = 100000 × 100 ≈ 83300 10 120
Correct Option: C
Suppose Original price of car = Rs. y
C.P. of car for Amit = 90 × y = Rs. 9y 100 10 Actual C.P. = Rs. 9y + 5000 10
According to the question,9y + 5000 × 120 = 100000 10 100 ⇒ 9y + 5000 = 100000 × 100 ≈ 83300 10 120 ⇒ 9y ≈ 83300 - 5000 ≈ 78300 10 ⇒ y ≈ 78300 × 10 ≈ Rs. 87000 9
- A fruit seller buys 240 apples for Rs. 600. Some of these apples are bad and are thrown away. He sells the remaining apples at Rs. 3.50 each and makes a profit of Rs.198. The percent of apples thrown away are
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Here , C.P. of 240 apples = Rs. 600.
C.P. of an apple = 600 = Rs. 2.5 240
S.P. of an apple = Rs. 3.5
Total profit = Rs. 198
Total S.P. = Rs. (600 + 198) = Rs. 798∴ Number of apples sold = 798 = 228 3.5
∴ Bad apples = 240 – 228 = 12
Correct Option: C
Here , C.P. of 240 apples = Rs. 600.
C.P. of an apple = 600 = Rs. 2.5 240
S.P. of an apple = Rs. 3.5
Total profit = Rs. 198
Total S.P. = Rs. (600 + 198) = Rs. 798∴ Number of apples sold = 798 = 228 3.5
∴ Bad apples = 240 – 228 = 12∴ Required percent = 12 × 100 = 5 % 240