Profit and Loss


  1. A man purchased some eggs at the rate of Rs. 10 per dozen and again purchased (3 / 4) of them at the rate of Rs. 12 per dozen. Then he sold all eggs at the rate of Rs. 13 per dozen and made a profit of Rs. 30. Find the total number of eggs he purchased altogether.









  1. View Hint View Answer Discuss in Forum

    Let the total number of eggs be y dozens.

    ∴ Total C.P = Rs.10y + 3y × 12
    4

    Total C.P = Rs.40y + 36y
    4

    Total C.P = Rs.
    76y
    = Rs. 19y
    4

    Total S.P. = y + 3y × 13
    4

    Total S.P =
    7 × 13y
    = Rs.
    91y
    44

    Correct Option: A

    Let the total number of eggs be y dozens.

    ∴ Total C.P = Rs.10y + 3y × 12
    4

    Total C.P = Rs.40y + 36y
    4

    Total C.P = Rs.
    76y
    = Rs. 19y
    4

    Total S.P. = y + 3y × 13
    4

    Total S.P =
    7 × 13y
    = Rs.
    91y
    44

    91y
    - 19y = 30
    4

    ⇒ 91y – 76y = 30 × 4
    ⇒ 15y = 30 × 4
    ∴ y =
    30 × 4
    = 8 dozens.
    15

    Hence , the total number of eggs be 8 dozens.


  1. Bimalbabu sells two cars each of Rs. 99,000. He makes a profit of 10% on the first car, but incurs a loss of 10% on the second. What will be his percentage of profit or loss on the whole transaction ?









  1. View Hint View Answer Discuss in Forum

    From the given question ,

    C.P. of car sold at 10% profit =
    100
    × S.P.
    100 + gain%

    C.P. of car =
    100
    × 99000 = Rs. 90000
    90

    C.P. of car sold at 10% loss =
    100
    × 99000 = Rs. 110000
    90

    Total C.P. = Rs. (90000 + 110000) = Rs. 200000
    Total S.P. = Rs. 2 × 99000 = Rs. 198000
    ∴ Loss = 200000 - 198000 = Rs. 2000
    ∴ Loss% =
    2000
    × 100 = 1%
    200000

    Second Method to solve this question :
    If two things are sold at the same price and loss and gain per cent be same i.e. y% then there is always loss
    Loss % =
    y2
    %
    100

    Correct Option: B

    From the given question ,

    C.P. of car sold at 10% profit =
    100
    × S.P.
    100 + gain%

    C.P. of car =
    100
    × 99000 = Rs. 90000
    90

    C.P. of car sold at 10% loss =
    100
    × 99000 = Rs. 110000
    90

    Total C.P. = Rs. (90000 + 110000) = Rs. 200000
    Total S.P. = Rs. 2 × 99000 = Rs. 198000
    ∴ Loss = 200000 - 198000 = Rs. 2000
    ∴ Loss% =
    2000
    × 100 = 1%
    200000

    Second Method to solve this question :
    If two things are sold at the same price and loss and gain per cent be same i.e. y% then there is always loss
    Loss % =
    y2
    %
    100

    Loss % =
    10 × 10
    = 1%
    100



  1. A publisher printed 3000 copies of a book for sale, the cost of each book being Rs. 7.00. He distributed 500 copies to different institutions free of cost. He allowed a book free of cost for each 24 books purchased. If the price of each book is fixed at Rs. 14.50. determine the rate of profit or loss of the publisher.









  1. View Hint View Answer Discuss in Forum

    On the basis of given details in question ,
    Total cost of the books = Rs. (3000 × 7) = Rs. 21000
    500 books are given free of cost.
    Selling price for 25 books = 24 × 14.50 = Rs. 348
    ∴ Total selling price = Rs. 34800
    ∴ Gain = Rs. (34800 – 21000) = Rs. 13800

    Correct Option: B

    On the basis of given details in question ,
    Total cost of the books = Rs. (3000 × 7) = Rs. 21000
    500 books are given free of cost.
    Selling price for 25 books = 24 × 14.50 = Rs. 348
    ∴ Total selling price = Rs. 34800
    ∴ Gain = Rs. (34800 – 21000) = Rs. 13800

    ∴ Gain% =
    13800
    × 100 ≈ 66%
    21000


  1. A salesman mixes two varieties of tea, whose costs are Rs. 60 and Rs. 45 per kg respectively. In what proportion the two varieties are to be mixed so as to make a profit of 25% if the sale price be Rs. 62.50 per kg ?









  1. View Hint View Answer Discuss in Forum

    According to question ,

    C.P. of 1 kg of mixture at a profit of 25% =
    100
    × 62.50 = Rs. 50
    100 + 25


    Required ratio = Price of kind I of tea : Price of kind II of tea

    Correct Option: B

    According to question ,

    C.P. of 1 kg of mixture at a profit of 25% =
    100
    × 62.50 = Rs. 50
    100 + 25


    Required ratio = Price of kind I of tea : Price of kind II of tea
    Required ratio = 5 : 10 = 1 : 2



  1. A shopkeeper buys a product of Rs. 150 per kg. 15% of product was damaged. At what price (per kg.) should he sell the remaining so as to earn a profit of 20%?









  1. View Hint View Answer Discuss in Forum

    Let the shopkeeper buy 100 kg. of product.
    ⇒ C.P. of 100 kg. of product = Rs. (150 × 100) = Rs. 15000
    15% of products is damaged.
    Remaining weight of product = 100 - 15 = 85 kg
    At a profit of 20% ,

    ⇒ S.P. of 85 kg. of product = Rs.15000 × 120 = Rs. 18000
    100

    ∴ S.P. of 1 kg. of product = Rs.18000
    85

    Correct Option: D

    Let the shopkeeper buy 100 kg. of product.
    ⇒ C.P. of 100 kg. of product = Rs. (150 × 100) = Rs. 15000
    15% of products is damaged.
    Remaining weight of product = 100 - 15 = 85 kg
    At a profit of 20% ,

    ⇒ S.P. of 85 kg. of product = Rs.15000 × 120 = Rs. 18000
    100

    ∴ S.P. of 1 kg. of product = Rs.18000
    85

    S.P. of 1 kg. of product =
    3600
    = Rs. 211
    13
    1717