Profit and Loss
- Ramesh bought 10 cycles for $ 500 each. He spent $ 2,000 on the repair of all cycles. He sold five of them for $ 750 each and the remaining for $ 550 each. Then the total gain or loss % is
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Here , Ramesh bought 10 cycles for $ 500 each and spent $ 2,000 on the repair of all cycles .
Total actual C.P. = $ (500 × 10 + 2000) = $ 7000
And total S.P. = $ (5 × 750 + 5 × 550) = $ (3750 + 2750) = $ 6500
Loss = Total S.P. - Total C.P. = $ 7000 – 6500 = $ 500Loss percent = 500 × 100 7000
Correct Option: D
Here , Ramesh bought 10 cycles for $ 500 each and spent $ 2,000 on the repair of all cycles .
Total actual C.P. = $ (500 × 10 + 2000) = $ 7000
And total S.P. = $ (5 × 750 + 5 × 550) = $ (3750 + 2750) = $ 6500
Loss = Total S.P. - Total C.P. = $ 7000 – 6500 = $ 500Loss percent = 500 × 100 7000 Loss percent = 50 = 7 1 % 7 7
- A table is sold at Rs. 1,800 at a loss of 10%. At what price should it be sold to earn a profit of 15%?
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Let C.P. of table = Rs. y .
According to question,y × 90 = 1800 100 ⇒ y = 1800 × 100 = Rs. 2000 90
For a profit of 15%,S.P. = 2000 × 115 = Rs. 2300 100
We can find required answer with the help of given formula :
S.P. = $ 1800 , Loss%= 10%C.P. = S P 
100 
100 - loss% C.P. = 1800 100 100 - 10 C.P. = 180000 = Rs. 2000 90 Now New S.P. = C.P. 100 + profit% 100
Correct Option: D
Let C.P. of table = Rs. y .
According to question,y × 90 = 1800 100 ⇒ y = 1800 × 100 = Rs. 2000 90
For a profit of 15%,S.P. = 2000 × 115 = Rs. 2300 100
We can find required answer with the help of given formula :
S.P. = $ 1800 , Loss%= 10%C.P. = S P 100 100 - loss% C.P. = 1800 100 100 - 10 C.P. = 180000 = Rs. 2000 90 Now New S.P. = C.P. 100 + profit% 100 New S.P. = 2000 100 + 15 100 New S.P. = 2000× 115 = Rs. 2300 100
- I purchased 120 exercise books at the rate of $ 3 each and sold (1 / 3) of them at the rate of $ 4 each, (1 / 2) of them at the rate of $ 5 each and the rest at the cost price. My profit percent was
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Given that , CP of 120 excercise books = $ (120 × 3) = $ 360
From the question ,
SP of 40 at $ 4 each = $ (40 × 4) = $ 160
SP of 60 at $ 5 each = $ (60 × 5) = $ 300
SP of remaining $ 20 books = $ (20 × 3) = $ 60
Total SP = $ (160 + 300 + 60) = $ 520
Profit = Total SP - Total CP = $ (520 – 360) = $ 160∴ Profit percent = 160 × 100 360
Correct Option: B
Given that , CP of 120 excercise books = $ (120 × 3) = $ 360
From the question ,
SP of 40 at $ 4 each = $ (40 × 4) = $ 160
SP of 60 at $ 5 each = $ (60 × 5) = $ 300
SP of remaining $ 20 books = $ (20 × 3) = $ 60
Total SP = $ (160 + 300 + 60) = $ 520
Profit = Total SP - Total CP = $ (520 – 360) = $ 160∴ Profit percent = 160 × 100 360 Profit percent = 400 = 44 4 % 9 9
- A person bought some articles at the rate of 5 per rupee and the same number at the rate of 4 per rupee. He mixed both the types and sold at the rate of 9 for 2 rupees. In this business he suffered a loss of $ 3. The total number of articles bought by him was
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Let the person buy 10 articles.
Total CP = $ 1 + 5 4 Total CP = $ 9 4
Correct Option: B
Let the person buy 10 articles.
Total CP = $ 1 + 5 4 Total CP = $ 9 4 SP of 10 articles = $ 2 × 10 = $ 20 9 9
Now, if loss is $ (1 / 36), number of articles = 10
∴ If loss is 3, number of articles = 36 × 10 × 3 = 1080
- A man bought pencils at the rate of 6 for $ 4 and sold them at the rate of 4 for $ 6. His gain% in the transaction is :
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Let the number of pencils bought = LCM of 4, 6 = 12
CP of 6 pencils = $ 4
∴ CP of 12 pencils = $ 8
S.P. of 4 pencils = $ 6
∴ S.P. of 12 pencils = $ 18
Profit = S.P. of 12 pencils - C.P. of 12 pencils = Rs. (18 – 8) = $ 10∴ Profit % = 10 × 100 = 125 % 8
We can find required answer with the help of given formula :
Here, a = 6, p = 4 and b = 4, q = 6Gain % = aq - bp × 100% bp
Correct Option: C
Let the number of pencils bought = LCM of 4, 6 = 12
CP of 6 pencils = $ 4
∴ CP of 12 pencils = $ 8
S.P. of 4 pencils = $ 6
∴ S.P. of 12 pencils = $ 18
Profit = S.P. of 12 pencils - C.P. of 12 pencils = Rs. (18 – 8) = $ 10∴ Profit % = 10 × 100 = 125 % 8
We can find required answer with the help of given formula :
Here, a = 6, p = 4 and b = 4, q = 6Gain % = aq - bp × 100% bp Gain % = 6 × 6 - 4 × 4 × 100% 4 × 4 Gain % = 36 - 16 × 100% 16 Gain % = 20 × 100 = 125 % 16
