Profit and Loss
- A trader had 22 quintals of wheat. He sold a part of it at 23% profit and the rest at 33% profit, so that he made a total profit of 27%. How much wheat did he sell at 33% profit?
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Let the C.P. of 1 quintal of wheat be Re.1.
Let the quantity of wheat sold at 33% profit be y quintals.
∴ Quantity of wheat sold at 23%
profit = (22 – y) quintals
According to the question ,y × 33 + (22 - y) × 23 = 22 × 27 100 100 100
⇒ 33y + 22 × 23 – 23y = 22 × 27
⇒ 10y + 506 = 594
Correct Option: C
Let the C.P. of 1 quintal of wheat be Re.1.
Let the quantity of wheat sold at 33% profit be y quintals.
∴ Quantity of wheat sold at 23%
profit = (22 – y) quintals
According to the question ,y × 33 + (22 - y) × 23 = 22 × 27 100 100 100
⇒ 33y + 22 × 23 – 23y = 22 × 27
⇒ 10y + 506 = 594
⇒ 10y = 594 – 506 = 88⇒ y = 88 = 8.8 quintals 10
⇒ y = (8.8 × 100) kg. = 880 kg.
- A merchant buys 25 litres of milk daily at the rate of Rs. 12 per litre. He mixes 5 litres of water in it and sells at the rate Rs. 10.40 per litre. His gain is :
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As per the given question ,
C.P. of 30 litre mixture of milk and water = Rs. (25 × 12) = Rs. 300
S.P. of 30 litre mixture = Rs. (30 × 10.40) = Rs. 312
Profit = Rs. (312 – 300) = Rs. 12∴ Profit percent = Profit × 100 C.P. of 30 litre mixture of milk and water
Correct Option: C
As per the given question ,
C.P. of 30 litre mixture of milk and water = Rs. (25 × 12) = Rs. 300
S.P. of 30 litre mixture = Rs. (30 × 10.40) = Rs. 312
Profit = Rs. (312 – 300) = Rs. 12∴ Profit percent = Profit × 100 C.P. of 30 litre mixture of milk and water Profit percent = 12 × 100 = 4% 300
- A man buys 3 type-I cakes and 6 type-II cakes for Rs. 900. He sells type-I cakes at a profit of 15% and type-II cakes at a loss of 10%. If his overall profit is Rs.30, the cost price (in Rs.) of a type-I and of a type-II cakes is
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Let the C.P. of each cake of type–I be Rs. x and that of type – II be Rs. y.
given in question ,
∴ 3x + 6y = 900
⇒ x + 2y = 300 ..... (i)Again, 3 × 115x + 6 × y × 90 = 930 100 100
⇒ 115x + 180q = 31000
By equation (i) × 2 – (ii),
Correct Option: B
Let the C.P. of each cake of type–I be Rs. x and that of type – II be Rs. y.
given in question ,
∴ 3x + 6y = 900
⇒ x + 2y = 300 ..... (i)Again, 3 × 115x + 6 × y × 90 = 930 100 100
⇒ 115x + 180q = 31000
By equation (i) × 2 – (ii),⇒ y = 3500 = Rs. 70 50
From equation (i), x + ( 2 × 70 ) = 300
⇒ x = Rs. (300 – 140) = Rs. 160
- A sells a watch to B and makes a loss of 12%. B makes a profit of (25 / 2) by selling the watch to C. If A sells the watch to B at the cost of which C purchased it, then the percentage of loss or profit of A will be
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Suppose C.P. for A = Rs. 100
C.P. for B at a loss of 12% = Rs. 88C.P. for C = 88 × 225 = Rs. 99 200
Loss = 100 - 99 = 1
Correct Option: A
Suppose C.P. for A = Rs. 100
C.P. for B at a loss of 12% = Rs. 88C.P. for C = 88 × 225 = Rs. 99 200
Loss = 100 - 99 = 1∴ Required loss percent = 1 × 100 = 1% 100
- A shopkeeper purchased 510 eggs at the rate of Rs. 20 per dozen. 30 eggs were broken on the way. In order to make a gain of 20%, he must sell the remaining eggs at the rate of
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Given in question , 30 eggs out of 510 eggs were broken.
Remaining eggs = 510 - 30 = 480 i.e. 40 dozen of eggs
C.P. of 12 eggs = Rs. 20∴ C.P. of 480 eggs = 510 × 20 = Rs. 850 12 ∴ C.P. of 1 dozen eggs = 850 =Rs. 21.25 40
∴ For a profit of 20%,
Correct Option: B
Given in question , 30 eggs out of 510 eggs were broken.
Remaining eggs = 510 - 30 = 480 i.e. 40 dozen of eggs
C.P. of 12 eggs = Rs. 20∴ C.P. of 480 eggs = 510 × 20 = Rs. 850 12 ∴ C.P. of 1 dozen eggs = 850 =Rs. 21.25 40
∴ For a profit of 20%,Required S.P. per dozen = Rs. 
21.25 × 120 
= Rs. 25.50 100
