Profit and Loss


  1. Rohit sold his car at 10% below the cost price to Amit. Amit got the car repaired and spent Rs. 5,000. He then sold the car to Rajesh at 20% above the total cost, which is equal to Rs. 1,00,000. Find the original price of the car (nearest to hundred).









  1. View Hint View Answer Discuss in Forum

    Suppose Original price of car = Rs. y

    C.P. of car for Amit =
    90 × y
    = Rs.
    9y
    10010

    Actual C.P. = Rs.9y + 5000
    10

    According to the question,
    9y + 5000 × 120 = 100000
    10100

    9y
    + 5000 =
    100000 × 100
    ≈ 83300
    10120


    Correct Option: C

    Suppose Original price of car = Rs. y

    C.P. of car for Amit =
    90 × y
    = Rs.
    9y
    10010

    Actual C.P. = Rs.9y + 5000
    10

    According to the question,
    9y + 5000 × 120 = 100000
    10100

    9y
    + 5000 =
    100000 × 100
    ≈ 83300
    10120

    9y
    ≈ 83300 - 5000 ≈ 78300
    10

    ⇒ y ≈
    78300 × 10
    ≈ Rs. 87000
    9


  1. A fruit seller buys 240 apples for Rs. 600. Some of these apples are bad and are thrown away. He sells the remaining apples at Rs. 3.50 each and makes a profit of Rs.198. The percent of apples thrown away are









  1. View Hint View Answer Discuss in Forum

    Here , C.P. of 240 apples = Rs. 600.

    C.P. of an apple =
    600
    = Rs. 2.5
    240

    S.P. of an apple = Rs. 3.5
    Total profit = Rs. 198
    Total S.P. = Rs. (600 + 198) = Rs. 798
    ∴ Number of apples sold =
    798
    = 228
    3.5

    ∴ Bad apples = 240 – 228 = 12

    Correct Option: C

    Here , C.P. of 240 apples = Rs. 600.

    C.P. of an apple =
    600
    = Rs. 2.5
    240

    S.P. of an apple = Rs. 3.5
    Total profit = Rs. 198
    Total S.P. = Rs. (600 + 198) = Rs. 798
    ∴ Number of apples sold =
    798
    = 228
    3.5

    ∴ Bad apples = 240 – 228 = 12
    ∴ Required percent =
    12
    × 100 = 5 %
    240



  1. A trader marks his goods 20% above cost price but allows his customers a discount of 10%, the cost price of a blackboard, which is sold for Rs. 216, is









  1. View Hint View Answer Discuss in Forum

    Let C.P. of article = Rs. 100
    ∴ Marked price = Rs. 120

    ∴ S.P. of article =
    120 × 90
    = Rs. 108
    100

    ∵ If S.P. = Rs. 108,
    C.P. = Rs. 100
    ∴ If S.P. = Rs. 216,

    Correct Option: C

    Let C.P. of article = Rs. 100
    ∴ Marked price = Rs. 120

    ∴ S.P. of article =
    120 × 90
    = Rs. 108
    100

    ∵ If S.P. = Rs. 108,
    C.P. = Rs. 100
    ∴ If S.P. = Rs. 216,
    C.P. =
    100
    × 216 = Rs. 200
    108


  1. A merchant bought 200 eggs, out of which 38 eggs were broken. He sold the remaining eggs at the rate of Rs. 4.80 per dozen and thus gained 8%. His total investment is









  1. View Hint View Answer Discuss in Forum

    Let. C.P. of 200 eggs be Rs. y,
    If 38 eggs are broken , then
    Remaining eggs = 200 – 38 = 162 eggs
    S.P. of remaining 12 eggs = Rs 4.80

    ∴ S.P. of remaining 162 eggs = Rs.
    1
    (162 × 4.80)
    12

    = Rs.777.6= Rs. 64.8
    12

    ∴ 108% of y = 64.8

    Correct Option: B

    Let. C.P. of 200 eggs be Rs. y,
    If 38 eggs are broken , then
    Remaining eggs = 200 – 38 = 162 eggs
    S.P. of remaining 12 eggs = Rs 4.80

    ∴ S.P. of remaining 162 eggs = Rs.
    1
    (162 × 4.80)
    12

    = Rs.777.6= Rs. 64.8
    12

    ∴ 108% of y = 64.8
    y × 108
    = 64.8
    100

    ⇒ y =
    64.8 × 100
    = Rs. 60
    108



  1. A milkman mixes water with milk and sells the mixture at the cost price of pure milk. The volume of water in litres to be mixed with each litre of milk to get a 25% profit is









  1. View Hint View Answer Discuss in Forum

    Suppose C.P. of 1 litre of milk = $ 1
    S.P. of 1 litre of mixture = $ 1

    ∴ C.P. of 1 litre of mixture =
    100
    × 1 = $
    4
    1255


    Milk : Water =
    4
    :
    1
    = 4 : 1
    55

    Sum of the Ratios = 4 + 1 = 5

    Correct Option: B

    Suppose C.P. of 1 litre of milk = $ 1
    S.P. of 1 litre of mixture = $ 1

    ∴ C.P. of 1 litre of mixture =
    100
    × 1 = $
    4
    1255


    Milk : Water =
    4
    :
    1
    = 4 : 1
    55

    Sum of the Ratios = 4 + 1 = 5
    Volume of water mixed =
    Ratio of water
    Sum of the ratios

    Volume of water mixed =
    1
    5