Rohit sold his car at 10% below the cost price to Amit.

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Rohit sold his car at 10% below the cost price to Amit. Amit got the car repaired and spent Rs. 5,000. He then sold the car to Rajesh at 20% above the total cost, which is equal to Rs. 1,00,000. Find the original price of the car (nearest to hundred).

Suppose Original price of car = Rs. y

C.P. of car for Amit =	90 × y	= Rs.	9y
	100		10

Actual C.P. = Rs.			9y	+ 5000
			10

According to the question,

			9y	+ 5000		×	120	= 100000
			10				100

⇒	9y	+ 5000	=	100000 × 100	≈ 83300
	10			120

⇒	9y	≈ 83300 - 5000 ≈ 78300
	10

⇒ y ≈	78300 × 10	≈ Rs. 87000
	9