Profit and Loss
- A person bought two articles A and B for $ 5,000. He sold A at 20% profit and B at 10% loss. He thus gained 2% on his outlay. The cost price of A was
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Given that , CP of two articles A and B = $ 5,000
Let the CP of article A be $ y
∴ CP of article B = $ (5000 – y)
According to the question,
120% of y + 90% of (5000 – y) = 102% of 5000
⇒ 120y + 450000 – 90y = 510000
⇒ 30y = 510000 – 450000 = 60000Correct Option: C
Given that , CP of two articles A and B = $ 5,000
Let the CP of article A be $ y
∴ CP of article B = $ (5000 – y)
According to the question,
120% of y + 90% of (5000 – y) = 102% of 5000
⇒ 120y + 450000 – 90y = 510000
⇒ 30y = 510000 – 450000 = 60000⇒ y = 60000 = $ 2000 30
Hence , The cost price of A is $ 2000 .
- A trader bought two horses for $ 19,500. He sold one at a loss of 20% and the other at a profit of 15%. If the selling price of each horse is the same, then their cost price are respectively.
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Given that , Total CP of two horses ( y ) = $ 19,500.
One of them is sold at a loss of a% and other is sold at a gain of b% and their S.P. is same.∴ C.P. of article sold at a loss of a% = 100 + b × y 200 - a + b
Here , a = 20 , b = 15%C.P. of first horse = 100 + 15 × 19500 200 - 20 + 15
Correct Option: B
Given that , Total CP of two horses ( y ) = $ 19,500.
One of them is sold at a loss of a% and other is sold at a gain of b% and their S.P. is same.∴ C.P. of article sold at a loss of a% = 100 + b × y 200 - a + b
Here , a = 20 , b = 15%C.P. of first horse = 100 + 15 × 19500 200 - 20 + 15 C.P. of first horse = 115 × 19500 = $ 11500 195
⇒ C.P. of second horse = 19500 - 11500 = $ 8000
- A man buys a field of agricultural land for $ 3,60,000. He sells one- third at a loss of 20% and two- fifths at a gain of 25%. At what price must he sell the remaining field so as to make an overall profit of 10 %?
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Here , CP of total agricultural field = $ 3,60,000
SP of total agricultural field = $ 
360000 × 110 
= $ 396000 100 SP of one–third of the field = 1 × 360000 × 80 = $ 96000 3 100 SP of 2 th of the field 5
Correct Option: C
Here , CP of total agricultural field = $ 3,60,000
SP of total agricultural field = $ 360000 × 110 = $ 396000 100 SP of one–third of the field = 1 × 360000 × 80 = $ 96000 3 100 SP of 2 th of the field 5 Or SP of two –fifth of the field = 2 × 360000 × 125 = $ 180000 5 100
∴ SP of the remaining field = $ (396000 – 96000 – 180000) = $ 120000
- Two-third of a consignment was sold at a profit of 5% and the remainder at a loss of 2%. If the total profit was $ 400, then the value of the consignment was
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Given that , Total profit = $ 400
Let the price of the sent items be y.
According to the question,2y × 5 - y × 2 = 400 3 100 3 100 ⇒ 10y - 2y = 400 × 100 3 3
Correct Option: A
Given that , Total profit = $ 400
Let the price of the sent items be y.
According to the question,2y × 5 - y × 2 = 400 3 100 3 100 ⇒ 10y - 2y = 400 × 100 3 3 ⇒ 8y = 40000 3 ⇒ y = 4000 × 3 = $ 15000 8
- A car and a jeep were sold for $ 121000 each. The car was sold at a loss of 20% while the jeep at a gain of 20%. The entire transaction resulted in
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Given in question , Total SP of car and jeep = 240000
CP of car = $ 100 × 120000 = $ 150000 80
Correct Option: C
Given in question , Total SP of car and jeep = 240000
CP of car = $ 100 × 120000 = $ 150000 80 CP of jeep = $ 100 × 120000 = $ 100000 120
Total CP = 150000 + 100000 = $ 250000
∴ Loss = Total CP - Total SP
∴ Loss = (250000 – 240000) = $ 10000
