Percentage
- If three-fifth of sixty percent of a number is 36, the number is
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Let the number be p.
∴ 3 × 60 × p = 36 5 100
Correct Option: A
Let the number be p.
∴ 3 × 60 × p = 36 5 100 ⇒ p = 36 × 5 × 5 = 100 3 × 3
- A dozen pairs of socks quoted at ₹180 are available at discount of 20%. How many pairs of socks can be bought for ₹48?
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According to question ,
∵ S.P. of a dozen pairs of socks = 180 × 80 = ₹144 100 ∴ S.P. of 1 pair of socks = 144 = ₹12 12
Correct Option: B
According to question ,
∵ S.P. of a dozen pairs of socks = 180 × 80 = ₹144 100 ∴ S.P. of 1 pair of socks = 144 = ₹12 12 ∴ No. of pairs available for ₹ 48 = 48 = 4 12
- A box has 100 blue balls, 50 red balls, 50 black balls. 25% of blue balls and 50% of red balls are taken away. Percentage of black balls at present is
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After taking away respective balls, Number of balls in the box = 75 + 25 + 50 = 150
∴ Percentage of black balls = 50 × 100 150
Correct Option: C
After taking away respective balls, Number of balls in the box = 75 + 25 + 50 = 150
∴ Percentage of black balls = 50 × 100 150 Required answer = 100 = 33 1 % 3 3
- In a college, 40% of the students were allotted group A, 75% of the remaining were given group B and the remaining 12 students were given group C. Then the number of students who applied for the group is
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Given that , Group A = 40%
Group B = 60 × 75 = 45% 100
Group C = 15%
If the total number of students be p, thenp × 15 = 12 100
Correct Option: C
Given that , Group A = 40%
Group B = 60 × 75 = 45% 100
Group C = 15%
If the total number of students be p, thenp × 15 = 12 100 ⇒ p = 12 × 100 = 80 15
- A number is divided into two parts in such a way that 80% of 1st part is 3 more than 60% of 2nd part and 80% of 2nd part is 6 more than 90% of the 1st part. Then the number is
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First part = p and second part = q.
∴ p × 80 = q × 60 100 100 ⇒ 4p = 3q + 3 5 5
⇒ 4p – 3q = 15 ...(i)
Again,4q = 9p + 6 5 10
⇒ 8q = 9p + 60
⇒ 8q – 9p = 60 ...(ii)
By equation (i) × 8 + (ii) × 3,
32p – 24q = 120
24q – 27p = 180
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5p = 300 ⇒ p = 60
Correct Option: C
First part = p and second part = q.
∴ p × 80 = q × 60 100 100 ⇒ 4p = 3q + 3 5 5
⇒ 4p – 3q = 15 ...(i)
Again,4q = 9p + 6 5 10
⇒ 8q = 9p + 60
⇒ 8q – 9p = 60 ...(ii)
By equation (i) × 8 + (ii) × 3,
32p – 24q = 120
24q – 27p = 180
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5p = 300 ⇒ p = 60
From equation (i)
4 × 60– 3q = 15
⇒ 3q = 240 – 15 = 225⇒ q = 225 = 75 3
∴ p + q = 60 + 75 = 135