Percentage


  1. Starting with 8000 workers, the company increases the number of workers by 5%, 10% and 20% at the end of first, second and third year respectively. The number of workers in the fourth year was









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    Required number of workers

    = 8000 ×
    105
    ×
    110
    ×
    120
    = 11088
    100100100

    Correct Option: B

    Required number of workers

    = 8000 ×
    105
    ×
    110
    ×
    120
    = 11088
    100100100


  1. If “basis points” are defined so that 1 per cent is equal to 100 basis points, then by how many basis points is 82.5 per cent greater than 62.5 per cent ?









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    1% = 100 basis points
    ∴ 82.5% = 8250 basis points and 62.5% = 6250 basis points
    ∴ Required difference
    = 8250 – 6250
    = 2000 basis points

    Correct Option: D

    1% = 100 basis points
    ∴ 82.5% = 8250 basis points and 62.5% = 6250 basis points
    ∴ Required difference
    = 8250 – 6250
    = 2000 basis points



  1. In the last financial year, a car company sold 41,800 cars. In this year, the target is to sell 51,300 cars. By what per cent must the sale be increased ?









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    Percentage increase in sales

    =
    51300 - 41800
    × 100
    41800

    =
    9500
    =
    250
    = 22
    8
    %
    4181111

    Correct Option: D

    Percentage increase in sales

    =
    51300 - 41800
    × 100
    41800

    =
    9500
    =
    250
    = 22
    8
    %
    4181111


  1. In a motor of 120 machine parts, 5% parts were defective. In another motor of 80 machine parts, 10% parts were defective. For the two motors considered together, the percentage of defective machine parts was









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    Defective parts of 120 machine parts

    =
    120 × 5
    = 6
    100

    Defective parts of 80 machine parts
    =
    80 × 10
    = 8
    100

    Total defective parts
    = 6 + 8 = 14
    ∴ Required percent
    =
    20
    × 100 = 7%
    200

    Correct Option: A

    Defective parts of 120 machine parts

    =
    120 × 5
    = 6
    100

    Defective parts of 80 machine parts
    =
    80 × 10
    = 8
    100

    Total defective parts
    = 6 + 8 = 14
    ∴ Required percent
    =
    20
    × 100 = 7%
    200



  1. A line of length 1.5 metres was measured as 1.55 metres by mistake. What will be the value of error per cent ?









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    Error = (1.55 – 1.5) metre = 0.55 metre

    ∴ Error per cent =
    0.05
    × 100
    1.5

    =
    50
    =
    10
    = 22
    1
    %
    1533

    Correct Option: C

    Error = (1.55 – 1.5) metre = 0.55 metre

    ∴ Error per cent =
    0.05
    × 100
    1.5

    =
    50
    =
    10
    = 22
    1
    %
    1533