Percentage


  1. The price of an article is first decreased by 20% and then increased by 30%. If the resulting price is 416, the original price of the article is









  1. View Hint View Answer Discuss in Forum

    If the original price of article be ₹ x, then

    x ×
    80
    ×
    130
    = 416
    100100

    ⇒ x =
    416 × 100 × 100
    = ₹400
    80 × 130

    Aliter : Using Rule 5,
    Let the number be x
    The number increases by
    =-20 + 30 -
    20 × 30
    % = 4%
    100

    ⇒ x +
    4x
    = 416
    100

    104x
    = 416
    100

    x = 400

    Correct Option: C

    If the original price of article be ₹ x, then

    x ×
    80
    ×
    130
    = 416
    100100

    ⇒ x =
    416 × 100 × 100
    = ₹400
    80 × 130

    Aliter : Using Rule 5,
    Let the number be x
    The number increases by
    =-20 + 30 -
    20 × 30
    % = 4%
    100

    ⇒ x +
    4x
    = 416
    100

    104x
    = 416
    100

    x = 400


  1. A number increased by 22
    1
    % gives 98. The number is
    2









  1. View Hint View Answer Discuss in Forum

    If the number be x, then

    x ×
    245
    = 98
    200

    ∴ x =
    98 × 200
    = 80
    245

    Correct Option: C

    If the number be x, then

    x ×
    245
    = 98
    200

    ∴ x =
    98 × 200
    = 80
    245



  1. The price of an article is decreased by 10%. To restore its former value the new price must be increased by :









  1. View Hint View Answer Discuss in Forum

    Let the original price be ₹100
    New price after 10% decrease = ₹90
    In order to restore the price to its original value, it must be increased by ₹10
    % increase

    =
    10
    × 100 =
    100
    = 11
    1
    %
    9099

    Aliter : Using Rule 9,
    Required %
    =
    10
    × 100 %
    100 - 10

    =
    100
    % = 11
    1
    %
    99

    Correct Option: D

    Let the original price be ₹100
    New price after 10% decrease = ₹90
    In order to restore the price to its original value, it must be increased by ₹10
    % increase

    =
    10
    × 100 =
    100
    = 11
    1
    %
    9099

    Aliter : Using Rule 9,
    Required %
    =
    10
    × 100 %
    100 - 10

    =
    100
    % = 11
    1
    %
    99


  1. A number reduced by 25% becomes 225. What per cent should it be increased so that it becomes 375?









  1. View Hint View Answer Discuss in Forum

    Clearly, 75% of the number = 225

    ∴ Number =
    225 × 100
    = 300
    75

    Again, 125% of 300 = 375
    Hence, the number should be increased by 25%

    Correct Option: A

    Clearly, 75% of the number = 225

    ∴ Number =
    225 × 100
    = 300
    75

    Again, 125% of 300 = 375
    Hence, the number should be increased by 25%



  1. A number is increased by 20% and then again by 20%. By what per cent should the increased number be reduced so as to get back the original number ?









  1. View Hint View Answer Discuss in Forum

    Let the number be 100.
    After 20% increase, number = 120
    After 20% increase of 120, number

    = 120 ×
    120
    = 144
    100

    ∴ Per cent decrease
    =
    44
    × 100
    144

    =
    275
    = 30
    5
    %
    99

    Aliter : Using Rule 7 and Rule 8,
    Increase %
    =20 + 20 +
    20 × 20
    % = 44%
    100

    Required %
    =
    44
    × 100%
    100 + 44

    =
    4400
    %
    144

    =
    275
    % = 30
    5
    %
    99

    Correct Option: A

    Let the number be 100.
    After 20% increase, number = 120
    After 20% increase of 120, number

    = 120 ×
    120
    = 144
    100

    ∴ Per cent decrease
    =
    44
    × 100
    144

    =
    275
    = 30
    5
    %
    99

    Aliter : Using Rule 7 and Rule 8,
    Increase %
    =20 + 20 +
    20 × 20
    % = 44%
    100

    Required %
    =
    44
    × 100%
    100 + 44

    =
    4400
    %
    144

    =
    275
    % = 30
    5
    %
    99