Percentage
- In an examination, 1100 boys and 900 girls appeared. 50% of the boys and 40% of the girls passed the examination. The percentage of candidates who failed
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Failed candidates
= 1100 × 50 + 900 × 60 100 100
= 550 + 540 = 1090
∴ Required percentage= 1090 × 100 = 54.5% 2000
Aliter : Using Rule 25,
B = 1100, b = 50%, G = 900, g = 40%
Percentage of failed candidates= Bb + Gg % B + G = 1100 × 50 + 900 × 40 1100 + 900 = 55000 + 36000 2000 = 91 = 45.5% 2 Correct Option: D
Failed candidates
= 1100 × 50 + 900 × 60 100 100
= 550 + 540 = 1090
∴ Required percentage= 1090 × 100 = 54.5% 2000
Aliter : Using Rule 25,
B = 1100, b = 50%, G = 900, g = 40%
Percentage of failed candidates= Bb + Gg % B + G = 1100 × 50 + 900 × 40 1100 + 900 = 55000 + 36000 2000 = 91 = 45.5% 2
- In an examination in which full marks were 500, A got 10% less than B. B got 25% more than C. C got 20% less than D. If A got 360 marks, what percentage of full marks was obtained by D ?
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A = 360;
B = 360 × 100 = 400 90 C = 400 × 100 = 320 125 D = 320 × 100 = 400 80
∴ Required percentage= 400 × 100 = 80% 500 Correct Option: B
A = 360;
B = 360 × 100 = 400 90 C = 400 × 100 = 320 125 D = 320 × 100 = 400 80
∴ Required percentage= 400 × 100 = 80% 500
- A student scored 32% marks in science subjects out of 300. How much should he score in language papers out of 200 if he is to get overall 46% marks ?
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46% of 500
= 500 × 46 = 230 100 32% of 300 = 300 × 32 = 96 100
Required marks = 230 – 96 = 134
Let x% of 200 = 134⇒ 200 × x = 134 100
⇒ 2x = 134⇒ x = 134 = 67% 2 Correct Option: B
46% of 500
= 500 × 46 = 230 100 32% of 300 = 300 × 32 = 96 100
Required marks = 230 – 96 = 134
Let x% of 200 = 134⇒ 200 × x = 134 100
⇒ 2x = 134⇒ x = 134 = 67% 2
- For an examination it is required to get 36 % of maximum marks to pass. A student got 113 marks and failed by 85 marks. The maximum marks for the examination are :
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Let maximum marks be x,
then,36 × x = 113 + 85 = 198 100 ⇒ x = 198 × 100 = 550 36
Aliter : Using Rule 24,
a = 36%, b = 113, c = 85
Maximum marks= (b + c) × 100 a = (113 + 85) × 100 36 = 198 × 100 = 550 36 Correct Option: B
Let maximum marks be x,
then,36 × x = 113 + 85 = 198 100 ⇒ x = 198 × 100 = 550 36
Aliter : Using Rule 24,
a = 36%, b = 113, c = 85
Maximum marks= (b + c) × 100 a = (113 + 85) × 100 36 = 198 × 100 = 550 36
- In an examination, a student had to obtain 33% of the maximum marks to pass. He got 125 marks and failed by 40 marks. The maximum marks were
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Let the maximum marks be x.
∴ x × 33 = 125 + 40 = 165 100 ⇒ x = 165 × 100 = 500 33
Aliter : Using Rule 24,
a = 33%, b = 125, c = 40
Maximum marks= (b + c) × 100 a = (125 + 40) × 100 33 = 165 × 100 = 500 33 Correct Option: A
Let the maximum marks be x.
∴ x × 33 = 125 + 40 = 165 100 ⇒ x = 165 × 100 = 500 33
Aliter : Using Rule 24,
a = 33%, b = 125, c = 40
Maximum marks= (b + c) × 100 a = (125 + 40) × 100 33 = 165 × 100 = 500 33
