271. A's salary is 20% less than B' s salary. Then B's salary is more than A's salary by

1. 1. 33¹/₂%

   
   
   

   2. 16²/₃%

   
   
   

   3. 20%

   
   
   

   4. 25%

   
   
   

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1. View Hint View Answer Discuss in Forum

   Given, a = 20%
   Required percentage = [a/(100 - a)] x 100%
   = [20/(100 - 20)] x 100%

   Correct Option: D

   Given, a = 20%
   Required percentage = [a/(100 - a)] x 100%
   = [20/(100 - 20)] x 100%
   = (20/80) x 100%
   = 25%

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272. The price of 10% increased of an article of ₹ 100, then again 10% increased the price. How much is increased in total price.
     

1. 1. 20

   
   
   

   2. 21

   
   
   

   3. 110

   
   
   

   4. 121

   
   
   

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1. View Hint View Answer Discuss in Forum

   10% of 100 = 10
   New price = 110
   
   Again, 10% of 110 = 110 x (10/100) = 11
   New price = 110 + 11 = 121

   Correct Option: B

   10% of 100 = 10
   New price = 110
   
   Again, 10% of 110 = 110 x (10/100) = 11
   New price = 110 + 11 = 121
   
   ∴ Required increment = 121 - 100 = 21

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273. 8 litres of water is added to 32 litres of a solution containing 20% of alcohol in water. What is the approximate concentration of alcohol in the solution now ?

1. 1. 24%

   
   
   

   2. 16%

   
   
   

   3. 8%

   
   
   

   4. 12%

   
   
   

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1. View Hint View Answer Discuss in Forum

   In 32 litres of solution,
   

   Alcohol =	32 × 20	= 6.4 litres
   	100

   
   Water = 32 – 6.4 = 25.6 litres
   On adding 8 litres of water,
   

   Correct Option: B

   In 32 litres of solution,
   

   Alcohol =	32 × 20	= 6.4 litres
   	100

   
   Water = 32 – 6.4 = 25.6 litres
   On adding 8 litres of water,
   

   Required percent =	6.4	× 100 = 16%
   	40

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274. A sugar solution of 3 litre contain 60% sugar. One liter of water is added to this solution. Then the percentage of sugar in the new solution is:

1. 1. 30

   
   
   

   2. 45

   
   
   

   3. 50

   
   
   

   4. 60

   
   
   

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1. View Hint View Answer Discuss in Forum

   According to question ,
   

   Quantity of sugar in the solution =	3 × 60	= 1.8 units
   	100

   
   On adding 1 litre of water,
   

   Correct Option: B

   According to question ,
   

   Quantity of sugar in the solution =	3 × 60	= 1.8 units
   	100

   
   On adding 1 litre of water,
   

   ∴ Required percent =	1.8	× 100 = 45%
   	4

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275. 300 grams of sugar solution has 40% of sugar in it. How much sugar should be added to make it 50% in the solution?

1. 1. 40 gram

   
   
   

   2. 10 gram

   
   
   

   3. 60 gram

   
   
   

   4. 80 gram

   
   
   

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1. View Hint View Answer Discuss in Forum

   In 300 gm of solution,
   

   Sugar =	300 × 40	= 120 gm.
   	100

   
   Let m gm of sugar be mixed.
   According to the question,
   

   	120 + m	=	1
   	300 + m		2

   
   

   Correct Option: C

   In 300 gm of solution,
   

   Sugar =	300 × 40	= 120 gm.
   	100

   
   Let m gm of sugar be mixed.
   According to the question,
   

   	120 + m	=	1
   	300 + m		2

   
   ⇒ 240 + 2m = 300 + m
   ⇒ 2m – m = 300 – 240
   ⇒ m = 60 gm.

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