Percentage

Percentage

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Aptitude miscellaneous
  1. Sahil got 45 marks in Hindi, 47 marks in Science, 49 marks in Mathematics, 45 marks in Social Science and 32 marks in English. The Maximum marks of each subject is 50. How much overall percentage of marks did he get ?










  1. View Hint View Answer Discuss in Forum

    Total marks obtained = [45 + 47 + 49 + 45 + 32] = 218
    Maximum marks = 5 x 50 = 250

    Correct Option: D

    Total marks obtained = [45 + 47 + 49 + 45 + 32] = 218
    Maximum marks = 5 x 50 = 250
    ∴ overall percentage = (218/250) x 100% = 87.2%

  1. In an examination, 25% students failed in mathematics 20% students failed in Mathematics, 20% failed in Economics and 5% failed in both. Find the percentage of students who passed in both the subjects.










  1. View Hint View Answer Discuss in Forum

    Here, x = 25, y = 20 and z = 5
    According to the formula,
    Required percentage = [100 - (25 + 20 - 5)]%

    Correct Option: A

    Here, x = 25, y = 20 and z = 5
    According to the formula,
    Required percentage = [100 - (25 + 20 - 5)]%
    = [100 - (45 - 5)]% = (100 - 40)% = 60%

  1. If the numerator of a fraction is increased by 200% and the denominator of the fraction is increased by 150%, the resultant fraction is 9/35 .What is the original fraction.










  1. View Hint View Answer Discuss in Forum

    Let the fraction be P/Q.
    Then, (P + 2P)/ Q + 3/2Q = 9/35

    Correct Option: C

    Let the fraction be P/Q.
    Then, (P + 2P)/ Q + 3/2Q = 9/35
    ⇒ (3P/5Q) x 2 = 9/35
    ∴ P/Q = (9/35) x (5/6) = 3/14

  1. The marked price of brand A watches is 15% higher than its original price. Due to increased in demand, the price is further increased by 10%. How much profit will be obtained in selling the watches ?










  1. View Hint View Answer Discuss in Forum

    Given that, a = 15% and b = 10%
    According to the formula,
    Required profit = a + b + (ab/100) %

    Correct Option: C

    Given that, a = 15% and b = 10%
    According to the formula,
    Required profit = a + b + (ab/100) %
    = 15 + 10 + (15 x 10)/100 %
    = (25 + 1.5)%
    = 26.5%
    = 26.5%

  1. A jogger desires to run a certain course in 1/4 less time than he usually takes. By What per cent must be increase his average running speed to accopplish the goal ?








  1. View Hint View Answer Discuss in Forum

    Let usual speed and usual time taken by the jogger are D and T, respectively.
    Let his new speed be D'. Then,
    DT = (3D'/4)T

    Correct Option: D

    Let usual speed and usual time taken by the jogger are D and T, respectively.
    Let his new speed be D'. Then,
    DT = (3D'/4)T
    ⇒ D = 3D'/4
    ⇒ D' = 4D/3

    Thus, he has to increased his speed by
    [(4D/3 - D) / D] x 100% .
    = 331/3 %