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Aptitude miscellaneous
  1. The price of ghee is increased by 32%. Therefore, a family reduces its consumption, so that the increment in price of ghee is only 10%. If consumption of ghee is 10 kg before the increment, then What is the consumption now ?








  1. View Hint View Answer Discuss in Forum

    Let price of ghee before increment = ₹ N

    Consumption = 10 kg
    Then, expenditure on ghee = ₹ 10N

    After increment,
    Expenditure on ghee = 110% of 10N = 11N
    Price of ghee = 132% of N = (N x 132)/100 = 33N/25 per kg

    Correct Option: A

    Let price of ghee before increment = ₹ N

    Consumption = 10 kg
    Then, expenditure on ghee = ₹ 10N

    After increment,
    Expenditure on ghee = 110% of 10N = 11N
    Price of ghee = 132% of N = (N x 132)/100 = 33N/25 per kg

    ∴ Now consumption = (11N x 25) / 33N kg
    = 81/3 kg

  1. The expenses on wheat, meat and vegetable of a family are in the ratio 12 : 17 : 3. The prices of these articles are increased by 20%, 30% and 50% respectively, The total expenses of the family on these articles are increased by ?










  1. View Hint View Answer Discuss in Forum

    Let expenses on wheat be 12N.
    Expenses on meat = 17N.
    Expenses on vegetables = 3N.
    ∴ Total expenses = 32N.

    Increased expenses = ₹ (120% of 12N) + (130% of 17N) + (150% of 3N)]

    Correct Option: B

    Let expenses on wheat be 12N.
    Expenses on meat = 17N.
    Expenses on vegetables = 3N.
    ∴ Total expenses = 32N.

    Increased expenses = ₹ (120% of 12N) + (130% of 17N) + (150% of 3N)]
    = ₹ [(120/100) x 12N] + [(130/100) x 17N] + [(150/100) x 3N]
    = ₹ [72N/5 + 221N/10 + 9N/2]
    = ₹ (144N + 221N + 45N)/10
    = ₹ 410N/10
    = ₹ 41

    ∴ Total increase percentage = (9N/32N) x 100 %
    = 225/8 %
    = 281/8%

  1. In 1998, ratio of the numbers of students taking examinations in x and z states are respectively 3 : 5 : 6. Next year, the numbers of students are increased by 20%, 10% and 20% respectively. If ratio of the numbers of students in states x and z is 1 : 2, then find the number of students who sit to take examination in 1998. ?










  1. View Hint View Answer Discuss in Forum

    In 1998
    Let number of students in x = 3k
    Number of students in y = 5k and
    Number of students in z = 6k

    Next year,
    number of students in x = 3k + 20% of 3k = 18k/5
    Number of students in y = 5k + 10% of 5k = 11k/2
    Number of students in z = 6k + 20% of 6k = 36k/5

    Correct Option: D

    In 1998
    Let number of students in x = 3k
    Number of students in y = 5k and
    Number of students in z = 6k

    Next year,
    number of students in x = 3k + 20% of 3k = 18k/5
    Number of students in y = 5k + 10% of 5k = 11k/2
    Number of students in z = 6k + 20% of 6k = 36k/5

    According to the question,
    (18k/5) / (36k/5) = 1/2
    Thus, data is insufficient.

  1. The tank-full of petrol in Arun's motor-cycle lasts for 10 days. If he starts using 25% more everyday, how many days will the tank-full of petrol last ?








  1. View Hint View Answer Discuss in Forum

    Let us assume that Arun uses N units of petrol everyday. so the amount of of petrol in the tank when it is full will be 10N. If he starts using 25% more petrol everyday. then the units of petrol he now use everyday will be
    N(1 + 25/100) = 1.25N

    So, the number of days his petrol will now last will be equal to (amount of petrol in tank) / (number of units used everyday)

    Correct Option: D

    Let us assume that Arun uses N units of petrol everyday. so the amount of of petrol in the tank when it is full will be 10N. If he starts using 25% more petrol everyday. then the units of petrol he now use everyday will be
    N(1 + 25/100) = 1.25N

    So, the number of days his petrol will now last will be equal to (amount of petrol in tank) / (number of units used everyday)
    = (10N) / (1.25N) = 10 / 1.25
    = 8 days

  1. In a examination out of 480 students, 85% of the girls and 70% of the boys passed. How many boys appeared in the examination, if total pass percentage was 75% ?










  1. View Hint View Answer Discuss in Forum

    Total number of students = 480
    percentage of total students passed = 75% of total student
    = (75 x 480)/100 = 360 students

    Now, using the condition from the question.
    Let the number of boys be N
    Then, 70% of N + 85% of (480 - N) = 360

    Correct Option: C

    Total number of students = 480
    percentage of total students passed = 75% of total student
    = (75 x 480)/100 = 360 students

    Now, using the condition from the question.
    Let the number of boys be N
    Then, 70% of N + 85% of (480 - N) = 360
    ⇒ [(70 x N)/100] + [85 x (480 - N)]/100 = 360
    ⇒ 70N - 85N + 40800 = 36000
    ⇒ 40800 - 36000 = 85N - 70N
    ⇒ 4800 = 15N
    ⇒ N = 4800/15 = 320
    ∴ There are 320 boys who appeared for the examination,