Percentage

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Aptitude miscellaneous
  1. In a examination it is required to get 36% of maximum marks to pass. A student got 113 marks and declared failed by 85 marks. The maximum marks are ?








  1. View Hint View Answer Discuss in Forum

    36% of N = (113 + 85)

    Correct Option: B

    ∵ 36% of N = (113 + 85)
    ∴ N = (100 x 198) / 36 = 550

  1. A candidate attempted 12 questions and secured full marks in all of them. If he obtained 60% in the test and each questions carried equal marks, then what was the total number of questions in the test ?








  1. View Hint View Answer Discuss in Forum

    Let the number of question be Y.
    60% of Y = 12

    Correct Option: D

    Let the number of question be Y.
    60% of Y = 12
    60Y / 100 =12
    Y = 20

  1. Pradeep spends 40 percent of his monthly income on food items and 50 percent of the remaining, on cloths and conveyance. He saves one-third of the remaining amount after spending on food, clothes and conveyance. If he saves Rs.19,200 every year, what is his monthly income ?








  1. View Hint View Answer Discuss in Forum

    From question,
    Food items = 40%
    Clothes + conveyance = 50% of 60% = 30%
    ⇒ Remaining amount = (100 - 40 - 30)% = 30%
    ∴ 1/3 of 30% = 19200
    ⇒ 10% = 19200
    ∴ 100% = Rs. 192000

    Correct Option: C

    From question,
    Food items = 40%
    Clothes + conveyance = 50% of 60% = 30%
    ⇒ Remaining amount = (100 - 40 - 30)% = 30%
    ∴ 1/3 of 30% = 19200
    ⇒ 10% = 19200
    ∴ 100% = Rs. 192000

    So his monthly income = 192000 / 12 = 16000

  1. Ashok gave 40 per cent of the amount he had to Jayant. Jayant in turn gave one-fourth of what he receive from Ashok to Prakash. After paying Rs. 200 to the taxi driver out of the amount he got from Jayant,Prakash now has Rs. 600 left with him.How much amount did Ashok have ?








  1. View Hint View Answer Discuss in Forum

    ∵ J = 40% of A =2A/5
    ⇒ P = 1/4 x 2A/5 = A/10
    ⇒ A/10 - 200 = 600

    Correct Option: C

    ∵ J = 40% of A =2A/5
    ⇒ P = 1/4 x 2A/5 = A/10
    ⇒ A/10 - 200 = 600
    ⇒ A/10 = 800
    ∴ A = Rs. 8000

  1. Rajesh solved 80 percent of the questions in an examination correctly, out of 41 questions solved by Rajesh 37 questions are correct and of the remaining questions out of 8 questions, 5 questions have been solved by Rajesh correctly then find the total number of question asked in the examination ?








  1. View Hint View Answer Discuss in Forum

    Suppose there are 8y questions were asked apart from the 41 question.Then
    37 + 5y/41 + 8y = 80% = 4/5
    ⇒ 185 + 25y = 164 + 32y
    ⇒ 7y = 21
    ⇒ y = 3

    Correct Option: B

    Suppose there are 8y questions were asked apart from the 41 question.Then
    37 + 5y/41 + 8y = 80% = 4/5
    ⇒ 185 + 25y = 164 + 32y
    ⇒ 7y = 21
    ⇒ y = 3
    ∴ Total no. of questions = 41 + 8 x 3 = 65.