Percentage
- The value of a property decreases every year at the rate of 5%. If its present value is ₹ 4,11,540, what was its value 3 years ago ?
-
View Hint View Answer Discuss in Forum
Using Rule 18,
Value of the property 3 years ago= P 
1 - R 
T 100 = 411540 1 - 5 3 100 = 411540 × 20 × 20 × 20 = ₹ 480000 19 × 19 × 19 Correct Option: D
Using Rule 18,
Value of the property 3 years ago= P 1 - R T 100 = 411540 1 - 5 3 100 = 411540 × 20 × 20 × 20 = ₹ 480000 19 × 19 × 19
- If the population of a town is 64000 and its annual increase is 10%, then its correct population at the end of 3 years will be :
-
View Hint View Answer Discuss in Forum
Using Rule 17,
Population of town= P 1 + R T 100 = 64000 1 + 10 3 100 = 64000 × 11 × 11 × 11 = 85184 10 10 10 Correct Option: B
Using Rule 17,
Population of town= P 1 + R T 100 = 64000 1 + 10 3 100 = 64000 × 11 × 11 × 11 = 85184 10 10 10
- The population of a village decreases at the rate of 20% per annum. If its population 2 years ago was 10,000, the present population is
-
View Hint View Answer Discuss in Forum
Using Rule 17,
Present population= 10000 1 - 20 2 100 = 10000 × 4 × 4 = 6400 5 5 Correct Option: B
Using Rule 17,
Present population= 10000 1 - 20 2 100 = 10000 × 4 × 4 = 6400 5 5
- If a man receives on one-fourth of his capital 3% interest, on two third 5% and on the remainder 11%, the percentage he receives on the whole is
-
View Hint View Answer Discuss in Forum
Required percent
= 1 × 3 + 2 × 5 + 1 - 1 - 2 × 11 4 3 4 3 = 3 + 10 + 11 = 9 + 40 + 11 = 5% 4 3 12 12 Correct Option: B
Required percent
= 1 × 3 + 2 × 5 + 1 - 1 - 2 × 11 4 3 4 3 = 3 + 10 + 11 = 9 + 40 + 11 = 5% 4 3 12 12
- The value of a machine is ₹ 6,250. It decreases by 10% during the first year, 20% during the second year and 30% during the third year. What will be the value of the machine after 3 years?
-
View Hint View Answer Discuss in Forum
Using Rule 28,
Required price of the machine= 6250 1 - 10 1 - 20 1 - 30 100 100 100 = 6250 × 90 × 80 × 70 = ₹ 3150 100 100 100 Correct Option: C
Using Rule 28,
Required price of the machine= 6250 1 - 10 1 - 20 1 - 30 100 100 100 = 6250 × 90 × 80 × 70 = ₹ 3150 100 100 100
