Percentage
- The number of employees working in a farm is increased by 25% and the wages per head are decreased by 25%. If it results in x % decrease in total wages, then the value of x is
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Let the original number of employees be 100 and wages per head be ₹100.
Total wages = ₹(100 × 100) = ₹10000
New number of employees = 125
New wages per head = ₹75
Total new wages = ₹(125 × 75) = ₹9375
Decrease
= ₹(10000 – 9375) = ₹625
∴ Percentage decrease= 625 × 100 10000 = 625 = 25 % 100 25 Correct Option: D
Let the original number of employees be 100 and wages per head be ₹100.
Total wages = ₹(100 × 100) = ₹10000
New number of employees = 125
New wages per head = ₹75
Total new wages = ₹(125 × 75) = ₹9375
Decrease
= ₹(10000 – 9375) = ₹625
∴ Percentage decrease= 625 × 100 10000 = 625 = 25 % 100 25
- A number is first decreased by 10% and then increased by 10%. The number so obtained is 50 less than the original number. The original number is
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Let original number be x.
∴ 90 x × 110 = x - 50 100 100 ⇒ 99x = x - 50 100 ⇒ x - 99x = 50 100 ⇒ x = 50 100
⇒ x = 5000
Aliter : Using Rule 3,
Let the number be xDecrease % = 102 % = 1% 100
⇒ x – 1% of x =x – 50x = 50 ⇒ x = 5000 100 Correct Option: B
Let original number be x.
∴ 90 x × 110 = x - 50 100 100 ⇒ 99x = x - 50 100 ⇒ x - 99x = 50 100 ⇒ x = 50 100
⇒ x = 5000
Aliter : Using Rule 3,
Let the number be xDecrease % = 102 % = 1% 100
⇒ x – 1% of x =x – 50x = 50 ⇒ x = 5000 100
- In an examination 73% of the candidates passed in quantitative aptitude test, 70% passed in General awareness and 64% passed in both. If 6300 failed in both subjects the total number of examiners was
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Percentage of students who
pass in one or two or both subjects = 73 + 70 – 64 = 79%
∴ Unsuccessful students
⇒ 100 – 79 = 21%
If the total number of examiners be x, then
21% of x = 6300⇒ x × 21 = 6300 100 ⇒ x = 6300 × 100 = 30000 21
Correct Option: C
Percentage of students who
pass in one or two or both subjects = 73 + 70 – 64 = 79%
∴ Unsuccessful students
⇒ 100 – 79 = 21%
If the total number of examiners be x, then
21% of x = 6300⇒ x × 21 = 6300 100 ⇒ x = 6300 × 100 = 30000 21
- 90% of the students in a school passed in English, 85% passed in Mathematics and 150 students passed in both the subjects. If no student failed in both the subjects, find the total number of students.
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If the total number of students be x, then
x = 90x + 85x - 150 100 100
⇒ 100x = 90x + 85x – 15000
⇒ 175x – 100x = 15000
⇒ 75x = 15000
⇒ x = 200
Correct Option: C
If the total number of students be x, then
x = 90x + 85x - 150 100 100
⇒ 100x = 90x + 85x – 15000
⇒ 175x – 100x = 15000
⇒ 75x = 15000
⇒ x = 200
- Three sets of 40, 50 and 60 students appeared for an examination and the pass percentage was 100, 90 and 80 respectively. The pass percentage of the whole set is
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Required percentage
= 40 × 100 + 50 × 90 + 60 × 80 40 + 50 + 60 = 88 2 % 3 Correct Option: A
Required percentage
= 40 × 100 + 50 × 90 + 60 × 80 40 + 50 + 60 = 88 2 % 3
