Percentage
- In the expression xy2, the values of both variables x and y are decreased by 20%. By this, the value of the expression is decreased by
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Let x = 10 and y = 10
∴ xy2 = 10 × 10 × 10=1000 units
Decreasing values of x and y by 20%,
Expression = xy2 = 8 × 8 × 8 = 512
Decrease= 1000–512 = 488 units
Percentage decrease= 488 × 100 = 48.8% 1000 Correct Option: C
Let x = 10 and y = 10
∴ xy2 = 10 × 10 × 10=1000 units
Decreasing values of x and y by 20%,
Expression = xy2 = 8 × 8 × 8 = 512
Decrease= 1000–512 = 488 units
Percentage decrease= 488 × 100 = 48.8% 1000
- p is six times as large as q. The per cent that q is less than p, is
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If a number is x% more than other, then the other number is less than the first number by
x × 100% 100
∴ Required answer= 500 × 100 = 500 × 100 100 + 500 600 = 250 = 83 1 3 3
Method 2 : Let q = x, p = 6x.
p – q = 6x – x = 5xIn % = 5x × 100 = 83 1 % 6x 3 Correct Option: A
If a number is x% more than other, then the other number is less than the first number by
x × 100% 100
∴ Required answer= 500 × 100 = 500 × 100 100 + 500 600 = 250 = 83 1 3 3
Method 2 : Let q = x, p = 6x.
p – q = 6x – x = 5xIn % = 5x × 100 = 83 1 % 6x 3
- X has twice as much money as that of Y and Y has 50% more money than that of Z. If the average money of all of them is 110, then the money, which X has, is
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Let z have x
∴ Money with Y = 3 x and 2
Money with X = 3x∴ 3x + 3x + x = 3 × 110 2 ⇒ 6x + 3x + 2x = 330 2
⇒ 11 x = 2 × 330⇒ x = 2 × 330 = 60 11
∴ Money with
X = 3x = ₹(3×60) = ₹ 180Correct Option: D
Let z have x
∴ Money with Y = 3 x and 2
Money with X = 3x∴ 3x + 3x + x = 3 × 110 2 ⇒ 6x + 3x + 2x = 330 2
⇒ 11 x = 2 × 330⇒ x = 2 × 330 = 60 11
∴ Money with
X = 3x = ₹(3×60) = ₹ 180
- An individual pays 30% income tax. On this tax he has to pay a surcharge of 10%. Thus, the net tax rate, he has to pay, is
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The net tax rate
= 30 + 30 × 10 % = 33% 100 Correct Option: C
The net tax rate
= 30 + 30 × 10 % = 33% 100
- Fresh fruit contains 68% water and dry fruit contains 20% water. How much dry fruit can be obtained from 100 kg of fresh fruits ?
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Water in 100 kg fresh fruit = 68%
Water in dry fruit = 20%
Decrease = 48%
∴ Dry fruit obtained
= 100 – 48 = 52 kg.Correct Option: C
Water in 100 kg fresh fruit = 68%
Water in dry fruit = 20%
Decrease = 48%
∴ Dry fruit obtained
= 100 – 48 = 52 kg.