Percentage


  1. In the annual examination Mahuya got 10% less marks than Supriyo in Mathematics. Mahuya got 81 marks. The marks of Supriyo are









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    Let marks obtained by Supriyo = x

    9x
    = 81
    10

    ⇒ x =
    81 × 10
    = 90
    9

    Correct Option: A

    Let marks obtained by Supriyo = x

    9x
    = 81
    10

    ⇒ x =
    81 × 10
    = 90
    9


  1. A student has to secure 40% marks to pass. He gets 90 marks and fails by 10 marks. Maximum marks are :









  1. View Hint View Answer Discuss in Forum

    Let the maximum marks be x.
    According to the question,
    40% of x = 90 + 10

    ⇒ x =
    100 × 100
    = 250
    40

    Aliter : Using Rule 24,
    a = 40%, b = 90, c = 10
    Maximum marks
    =
    (b + c)
    × 100
    a

    =
    (90 + 10)
    × 100 = 250
    40

    Correct Option: C

    Let the maximum marks be x.
    According to the question,
    40% of x = 90 + 10

    ⇒ x =
    100 × 100
    = 250
    40

    Aliter : Using Rule 24,
    a = 40%, b = 90, c = 10
    Maximum marks
    =
    (b + c)
    × 100
    a

    =
    (90 + 10)
    × 100 = 250
    40



  1. In an examination, 65% of the students passed in Mathematics, 48% passed in Physics and 30% passed in both. How much percent of students failed in both the subjects ?









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    n (M) = 65, n (P) = 48, n(M∩P) = 30
    ∴ n(M∪P)= n(M) + n(P) – n(M∩P)
    = 65 + 48 – 30 = 83
    ∴ Per cent of students passed = 83
    ∴ Per cent of students failed= 17
    Method 2 :
    Students passed only in Math
    = 65 – 30 = 35%
    Students passed only in Physics
    = 48 – 30 = 18%
    ∴ Total passing %
    = 35 + 18 + 30 = 83%
    ∴ Failed = 100 – 83 = 17%

    Correct Option: A

    n (M) = 65, n (P) = 48, n(M∩P) = 30
    ∴ n(M∪P)= n(M) + n(P) – n(M∩P)
    = 65 + 48 – 30 = 83
    ∴ Per cent of students passed = 83
    ∴ Per cent of students failed= 17
    Method 2 :
    Students passed only in Math
    = 65 – 30 = 35%
    Students passed only in Physics
    = 48 – 30 = 18%
    ∴ Total passing %
    = 35 + 18 + 30 = 83%
    ∴ Failed = 100 – 83 = 17%


  1. The cost of an article worth 100 is increased by 10% first and again increased by 10%. The total increase in rupees is









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    Using Rule 7,
    Percentage effect

    =10 + 10 +
    10 × 10
    % = 21%
    100

    ∴ Increase = ₹21

    Correct Option: B

    Using Rule 7,
    Percentage effect

    =10 + 10 +
    10 × 10
    % = 21%
    100

    ∴ Increase = ₹21



  1. The price of an article was decreased by 10% and again reduced by 10%. By what per cent should the price have been reduced once, in order to produce the same effect as these two successive reductions ?









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    Using Rule 6,
    A single equivalent reduction to reduction series of x%, y%

    =x + y -
    xy
    %
    100

    =10 + 10 -
    10 × 10
    %
    100

    = (20 - 1)% = 19%

    Correct Option: B

    Using Rule 6,
    A single equivalent reduction to reduction series of x%, y%

    =x + y -
    xy
    %
    100

    =10 + 10 -
    10 × 10
    %
    100

    = (20 - 1)% = 19%