Percentage
- The population of a town 2 years ago was 62,500. Due to migration to big cities, it decreases every year at the rate of 4%. The present population of the town is:
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Using Rule 18,
Let the present population be P∴ P = 62500 1 - 4 2 100 = 62500 × 24 × 24 = 57600 25 25 Correct Option: A
Using Rule 18,
Let the present population be P∴ P = 62500 1 - 4 2 100 = 62500 × 24 × 24 = 57600 25 25
- The population of a town increases every year by 4%. If its present population is 50,000, then after 2 years it will be
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Using Rule 17,
Required population= 50000 1 + 4 2 100 = 50000 × 26 × 26 = 54080 25 25 Correct Option: C
Using Rule 17,
Required population= 50000 1 + 4 2 100 = 50000 × 26 × 26 = 54080 25 25
- At an election there were two candidates. A candidate got 38% of votes and lost by 7200 number of votes. The total number of valid votes were
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Number of valid votes = x (let)
∴ (62 – 38)% of x = 7200⇒ x × 24 = 7200 100 ⇒ x = 7200 × 100 = 30000 24
Aliter : Using Rule 26,
Total number of votes= 50 × 7200 = 50 × 600 = 30000 50 - 38 Correct Option: D
Number of valid votes = x (let)
∴ (62 – 38)% of x = 7200⇒ x × 24 = 7200 100 ⇒ x = 7200 × 100 = 30000 24
Aliter : Using Rule 26,
Total number of votes= 50 × 7200 = 50 × 600 = 30000 50 - 38
- Present population of a village is 67600. It has been increasing annually at the rate of 4%. What was the population of the village two years ago ?
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Using Rule 17,
Population of the village two years ago= P 1 + R 2 100 = 67600 1 + 4 2 100 = 67600 × 25 × 25 = 62500 26 × 26 Correct Option: A
Using Rule 17,
Population of the village two years ago= P 1 + R 2 100 = 67600 1 + 4 2 100 = 67600 × 25 × 25 = 62500 26 × 26
- The value of a machine depreciates by 5% every year. If its present value is ₹ 2,00,000, its value after 2 years will be
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Using Rule 18,
A = P 1 - R T 100 = 200000 1 - 5 2 100 = 200000 × 19 × 19 = ₹ 180500 20 20 Correct Option: A
Using Rule 18,
A = P 1 - R T 100 = 200000 1 - 5 2 100 = 200000 × 19 × 19 = ₹ 180500 20 20