Percentage
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and after spending 75% of the remaining he had Rs. 370 left. How much money did he have?A man spends 7 1 % of his money 2
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Initial amount with the person = Rs. x (let)
After an expense of 15 % 2
Remaining amount= 100 - 15 % of x. 2 = 200 - 15 % of x 2 = 50 = 10 = 22 1 % 15 3 3
After an expense of 75% of it,Remaining amount = 37x = Rs. 37x 40 × 4 160
According to the question,37x = 370 ⇒ 37x = 370 × 160 160 ⇒ x = 370 × 160 = Rs. 1600 37 Correct Option: B
Initial amount with the person = Rs. x (let)
After an expense of 15 % 2
Remaining amount= 100 - 15 % of x. 2 = 200 - 15 % of x 2 = 50 = 10 = 22 1 % 15 3 3
After an expense of 75% of it,Remaining amount = 37x = Rs. 37x 40 × 4 160
According to the question,37x = 370 ⇒ 37x = 370 × 160 160 ⇒ x = 370 × 160 = Rs. 1600 37
- A businessman imported Laptops, worth Rs. 210000, Mobile phones worth Rs. 100000 and Television sets worth Rs. 150000. He had to pay 10% duty on laptops, 8% on Phones and 5% on Television sets as a special case. How much total duty (in Rupees) he had to pay on all items as per above details?
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Duty payment
Laptop ⇒ Rs. 210000 × 10 = Rs. 21000 100
Mobile phone⇒ Rs. 100000 × 8 = Rs. 8000 100
Television set⇒ Rs. 150000 × 5 = Rs. 7500 100
Total Duty Payment
= Rs. (21000 + 8000 + 7500)
= Rs. 36500Correct Option: A
Duty payment
Laptop ⇒ Rs. 210000 × 10 = Rs. 21000 100
Mobile phone⇒ Rs. 100000 × 8 = Rs. 8000 100
Television set⇒ Rs. 150000 × 5 = Rs. 7500 100
Total Duty Payment
= Rs. (21000 + 8000 + 7500)
= Rs. 36500
- A line of length 1.5 metres was measured as 1.55 metres by mistake. What will be the value of error per cent ?
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Error = (1.55 – 1.5) metre = 0.55 metre
∴ Error per cent = 0.05 × 100 1.5 = 50 = 10 = 22 1 % 15 3 3 Correct Option: C
Error = (1.55 – 1.5) metre = 0.55 metre
∴ Error per cent = 0.05 × 100 1.5 = 50 = 10 = 22 1 % 15 3 3
- In a motor of 120 machine parts, 5% parts were defective. In another motor of 80 machine parts, 10% parts were defective. For the two motors considered together, the percentage of defective machine parts was
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Defective parts of 120 machine parts
= 120 × 5 = 6 100
Defective parts of 80 machine parts= 80 × 10 = 8 100
Total defective parts
= 6 + 8 = 14
∴ Required percent= 20 × 100 = 7% 200 Correct Option: A
Defective parts of 120 machine parts
= 120 × 5 = 6 100
Defective parts of 80 machine parts= 80 × 10 = 8 100
Total defective parts
= 6 + 8 = 14
∴ Required percent= 20 × 100 = 7% 200
- In the last financial year, a car company sold 41,800 cars. In this year, the target is to sell 51,300 cars. By what per cent must the sale be increased ?
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Percentage increase in sales
= 51300 - 41800 × 100 41800 = 9500 = 250 = 22 8 % 418 11 11 Correct Option: D
Percentage increase in sales
= 51300 - 41800 × 100 41800 = 9500 = 250 = 22 8 % 418 11 11