Percentage
- The number of students appeared from a school for the Madhyamik Examination in three consecutive years are in the ratio 7 : 8 : 10 and 75%, 87.5% and 93.75% of the students of respective years were successful. What is the percentage of students who were successful during these three years taken together ?
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Number of successful students :
First Year ⇒ 7x × 75 = 21x = 5.25x 100 4 Second year ⇒ 8x × 87.5 = 7x 100 Third year ⇒ 10x × 93.75 = 9.375x 100
Total successful students
= 21.625x
Required percentage= 21.625x × 100 = 86.5% 25x Correct Option: B
Number of successful students :
First Year ⇒ 7x × 75 = 21x = 5.25x 100 4 Second year ⇒ 8x × 87.5 = 7x 100 Third year ⇒ 10x × 93.75 = 9.375x 100
Total successful students
= 21.625x
Required percentage= 21.625x × 100 = 86.5% 25x
- An alloy contains 89% of copper; find how much copper is to be mixed to a sample of alloy so as to get 44 kg of a new metal having 90% copper in it.
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In 100 gm of alloy, Copper = 89 gm.
Let x gm. of copper be mixed789 + x = 90 11 10
⇒ x = 99 – 89 = 10gm
To get 44 kg of new alloy, copper to be mixed= 44 × 1000 × 100 = 4 kg. 1100 Correct Option: D
In 100 gm of alloy, Copper = 89 gm.
Let x gm. of copper be mixed789 + x = 90 11 10
⇒ x = 99 – 89 = 10gm
To get 44 kg of new alloy, copper to be mixed= 44 × 1000 × 100 = 4 kg. 1100
- If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 300% the resultant fraction is
5 18
What is the original fraction?
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Let original fraction be x . y ∴ x × 250 = 5 y × 400 18 ⇒ x = 5 × 400 = 4 y 18 250 9 Correct Option: A
Let original fraction be x . y ∴ x × 250 = 5 y × 400 18 ⇒ x = 5 × 400 = 4 y 18 250 9
- An alloy of gold and silver weighs 50 gm. It contains 80% gold. How much gold should be added to the alloy so that percentage of gold is increased to 90?
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In original alloy,
Gold = 40 gm
Silver = 10 gm
Let x gm of gold is added.∴ 40 + x = 90 = 9 50 + x 100 10
⇒ 400 + 10x = 450 + 9x
⇒ x = 50 gm.Correct Option: C
In original alloy,
Gold = 40 gm
Silver = 10 gm
Let x gm of gold is added.∴ 40 + x = 90 = 9 50 + x 100 10
⇒ 400 + 10x = 450 + 9x
⇒ x = 50 gm.
- 5% of income of A is equal to 15% of income of B and 10% of income of B is equal to 20% of income of C. If income of C is 2000, then total income of A, B and C is:
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A × 5 = B × 15 100 100 ⇒ A = 15 = 3 B 5 1 Again, B × 10 = C × 20 100 100 B = 2 C 1
∴ A : B = 3 : 1 = 6 : 2
B : C = 2 : 1
∴ A : B : C = 6 : 2 : 1
∴ Total income = 9 × 2000 = Rs. 18000Correct Option: C
A × 5 = B × 15 100 100 ⇒ A = 15 = 3 B 5 1 Again, B × 10 = C × 20 100 100 B = 2 C 1
∴ A : B = 3 : 1 = 6 : 2
B : C = 2 : 1
∴ A : B : C = 6 : 2 : 1
∴ Total income = 9 × 2000 = Rs. 18000