Percentage


  1. 8% of the voters in an election did not cast their votes. In this election, there were only two candidates. The winner by obtaining 48% of the total votes defeated his contestant by 1100 votes. The total number of voters in the election was :









  1. View Hint View Answer Discuss in Forum

    Let the total number of votes be 100.
    Number of uncast votes = 8
    ∴ Number of votes polled = 92
    Number of votes obtained by the winner = 48
    ∴ Number of votes obtained by the loser = 92 – 48 = 44
    If the difference of win be 4 votes, total voters = 100
    ∴ When the difference be 1100 votes, total voters

    =
    100
    × 1100 = 27500
    4

    Aliter : Using Rule 21,
    Here, x = 1100, A = 48
    ∴ Total number of votes
    =
    50 × x
    50 - A

    =
    50 × 1100
    50 - 48

    =
    50 × 1100
    = 25 × 1100 = 27500
    2

    Correct Option: D

    Let the total number of votes be 100.
    Number of uncast votes = 8
    ∴ Number of votes polled = 92
    Number of votes obtained by the winner = 48
    ∴ Number of votes obtained by the loser = 92 – 48 = 44
    If the difference of win be 4 votes, total voters = 100
    ∴ When the difference be 1100 votes, total voters

    =
    100
    × 1100 = 27500
    4

    Aliter : Using Rule 21,
    Here, x = 1100, A = 48
    ∴ Total number of votes
    =
    50 × x
    50 - A

    =
    50 × 1100
    50 - 48

    =
    50 × 1100
    = 25 × 1100 = 27500
    2


  1. The value of a machine depreciates every year at the rate of 10% on its value at the beginning of that year. If the current value of the machine is ₹ 729, its worth 3 years ago was:









  1. View Hint View Answer Discuss in Forum

    Using Rule 18,
    If the price of machine 3 years ago be ₹ x. then

    729 = x1 -
    10
    3
    100

    ⇒ 729 = x
    9
    3⇒ x = ₹ 1000
    10

    Correct Option: A

    Using Rule 18,
    If the price of machine 3 years ago be ₹ x. then

    729 = x1 -
    10
    3
    100

    ⇒ 729 = x
    9
    3⇒ x = ₹ 1000
    10



  1. In an election between two candidates, the candidate getting 60% of the votes polled, is elected by a majority of 14,000 votes. The number of votes polled by the winning candidate is









  1. View Hint View Answer Discuss in Forum

    Difference of percentage of votes = 60% – 40% = 20%
    ∴ 20% of total votes = 14000
    ∴ 60% of total votes

    or x =
    14000
    × 60 = 42000
    20

    Correct Option: C

    Difference of percentage of votes = 60% – 40% = 20%
    ∴ 20% of total votes = 14000
    ∴ 60% of total votes

    or x =
    14000
    × 60 = 42000
    20


  1. In an office 40% of the staff is female, 40% of the females and 60% of the males voted for me. The percentage of votes I got was









  1. View Hint View Answer Discuss in Forum

    Let total employees = 100
    ∴ Required percentage

    =
    40 × 40
    +
    60 × 60
    = 16 + 36 = 52%
    100100

    Correct Option: D

    Let total employees = 100
    ∴ Required percentage

    =
    40 × 40
    +
    60 × 60
    = 16 + 36 = 52%
    100100



  1. In an election there were only two candidates. One of the candidates secured 40% of votes and is defeated by the other candidate by 298 votes. The total number of votes polled is









  1. View Hint View Answer Discuss in Forum

    Let votes polled = x

    ∴ x ×
    60 - 40
    = 298
    100

    ⇒ x ×
    1
    = 298
    5

    ⇒ x = 298 × 5 = 1490
    Aliter : Using Rule 26,
    Total number of votes
    =
    50 × 298
    = 1490
    50 - 40

    Correct Option: C

    Let votes polled = x

    ∴ x ×
    60 - 40
    = 298
    100

    ⇒ x ×
    1
    = 298
    5

    ⇒ x = 298 × 5 = 1490
    Aliter : Using Rule 26,
    Total number of votes
    =
    50 × 298
    = 1490
    50 - 40