Percentage
- When 60% of a number is subtracted from another number, the second number reduces to its 52%; the ratio of the first number to the second number is :
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Let the first number be p and second number be q.
∴ q - 60p = 52q 100 100
⇒ 100q – 60p = 52q
⇒ 48q = 60p
Correct Option: D
Let the first number be p and second number be q.
∴ q - 60p = 52q 100 100
⇒ 100q – 60p = 52q
⇒ 48q = 60p∴ p = 48 = 4 or 4 : 5 y 60 5
- The ratio of the number of boys and girls in a school is 3 : 2. If 20% of the boys and 25% of the girls are scholarship holders, then the percentage of the students, who do not get the scholarship, is :
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Let Boys = 30, Girls = 20
Boys getting no scholarship = 24
Girls getting no scholarship = 15
Sum = 24 + 15 = 39Correct Option: A
Let Boys = 30, Girls = 20
Boys getting no scholarship = 24
Girls getting no scholarship = 15
Sum = 24 + 15 = 39∴ Required percentage = 39 × 100 = 78% 50
- If 30% of (B – A) = 18% of (B + A), then the ratio A : B is equal to
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Given that , 30% of (B – A) = 18% of (B + A)
(B – A) × 30 = (B + A) × 18 100 100 ∴ B - A = 18 = 3 B + A 30 5
By componendo and dividendo,2B = 3 + 5 -2A 3 - 5
Correct Option: B
Given that , 30% of (B – A) = 18% of (B + A)
(B – A) × 30 = (B + A) × 18 100 100 ∴ B - A = 18 = 3 B + A 30 5
By componendo and dividendo,2B = 3 + 5 -2A 3 - 5 = 8 = 4 -2 -1 ⇒ B = 4 A 1
⇒ A : B = 1 : 4
- If A exceeds B by 60% and B is less than C by 20%, then A : C is
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Let C = 100
∴ B = 80A = 80 × 160 = 128 100
Correct Option: A
Let C = 100
∴ B = 80A = 80 × 160 = 128 100
∴ A : C = 128 : 100
Required ratio = 32 : 25
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If 60% of A = 3 of B, then A : B is 4
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A × 60 = B × 3 100 4 ⇒ A × 3 = B × 3 5 4
Correct Option: D
A × 60 = B × 3 100 4 ⇒ A × 3 = B × 3 5 4 ⇒ A = 3 × 5 = 5 : 4 B 4 3
Hence , required ratio is 5 : 4 .
