AB = 6 cm ; AD = 4 cm and ∠ BAD = 30°
Area of parallelogram ABCD = AB x AD x sin 30°

Correct Option: A

AB = 6 cm ; AD = 4 cm and ∠ BAD = 30°
Area of parallelogram ABCD = AB x AD x sin 30°
= 6 x 4 x sin 30° = 12 cm²

AB = 60 m, BC = 40 m and AC = 80 m
∴ s = (60 + 40 + 80 ) / 2 m = 90 m
(s-a) = 90 - 60 = 30 m,
(s-b) = 90 - 40 = 50 m and
(s-c) = 90 - 80 = 10 m

∴ Area of Δ ABC =
√s(s-a)(s-b)(s-c)
= √90 x 30 x 50 x 10 m²
= 300√15 m²

Correct Option: C

AB = 60 m, BC = 40 m and AC = 80 m
∴ s = (60 + 40 + 80 ) / 2 m = 90 m
(s-a) = 90 - 60 = 30 m,
(s-b) = 90 - 40 = 50 m and
(s-c) = 90 - 80 = 10 m

∴ Area of Δ ABC =
√s(s-a)(s-b)(s-c)
= √90 x 30 x 50 x 10 m²
= 300√15 m²

∴ Area of parallelogram ABCD = 2 x area of Δ ABC
= 600√15 m²

Area of trapezium = 1/2 x sum of parallel sides x perpendicular distance between them

Correct Option: C

Area of trapezium = 1/2 x sum of parallel sides x perpendicular distance between them
= 1/2 (1 + 2) x 6 m²
= 9 m²

Area of parallelogram = Side of parallelogram x distance from the opposite side

Correct Option: B

Area of parallelogram = Side of parallelogram x distance from the opposite side
= 14 x 16 cm²
= 224 cm²

Cross section area = 1/2 x ( a + b ) x d
Where a and b are the parallel sides, d is the perpendicular distance between them.

Correct Option: B

Cross section area = 1/2 x ( a + b ) x d
where a and b are the parallel sides, d is the perpendicular distance between them.
⇒ 1/2 x ( a + b ) x d = 640
⇒ d = (640 x 2) / 16 = 80m