Ratio of area of 2 squares = (ratio of perimeter of 2 squares)²

Correct Option: C

Ratio of area of 2 squares = (ratio of perimeter of 2 squares)²
= (24/12)²
= 4

Area of the field =1215/135 = 9 hec
= 90000 m² [1 hec =10000 m²]
∴ Side of the field = √90000 = 300 m

Correct Option: C

Area of the field =1215/135 = 9 hec
= 90000 m² [1 hec =10000 m²]
∴ Side of the field = √90000 = 300 m
Perimeter of the field = 4 x 300 = 1200 m

Now, cost of putting a fence around field = (1200 x 75)/100 = ₹ 900

Let length of rectangle = 5k
and breadth of rectangle = 3k

According to the quecation,
5k - 3k = 8

Required area = Lenght x Breadth

Correct Option: C

Let length of rectangle = 5k
and breadth of rectangle = 3k

According to the quecation,
5k - 3k = 8
⇒ 2k =8
∴ k = 4
∴ Lenght = 5k = 5 x 4 = 20 m
Breadth = 3k = 3 x 4 = 12 m

∴ Required area = Lenght x Breadth
= 20 x 12 = 240 sq m

Let the third side be x.
According to the question,
x + 20 = 26

Correct Option: A

Let the third side be x.
According to the question,
x + 20 = 26
⇒ x = 26 - 20 = 6 cm
∴ Each equal side = 20/2 = 10 cm

Number of tiles needed = (Area of square room) / (Area of tile)

Correct Option: C

Area of square room = (10)² = 100 sq m
= 100 x (100)² sq cm
= 100 x 100 x 100 sq cm

Now, area of tiles = (50)² = 50 x 50 sq cm
∴ Number of tiles needed = (Area of square room) / (Area of tile)
= (100 x 100 x 100) / (50 x 50)
= 400

Hence, 400 tiles will be needed.