Distance covered in 1 revolution
= (44 x 1000) / 4000
= 11 m

According to the question,
2πr = 11

Correct Option: E

Distance covered in 1 revolution
= (44 x 1000) / 4000
= 11 m

According to the question,
2πr = 11
⇒ (44/7) x r = 11
∴ r = (11 x 7) / 44 = 1.75 m

According to the question,
Area of semi- circle = 77 m
(1/2) x π x r² = 77

∴Circumference of semi- circle =πr + 2r
= ( π + 2)r

Correct Option: A

According to the question,
Area of semi- circle = 77 m
(1/2) x π x r² = 77
⇒ r² = (77 x 2 x 7)/22
∴ r = 7m

∴Circumference of semi- circle =πr + 2r
= ( π + 2)r
= [(22/7) + 2] x 7
= 36 m

Let the radius of the park be r, then
πr + 2r = 288

Area of the park = (1/2)πr²

Correct Option: A

Let the radius of the park be r, then
πr + 2r = 288
(π + 2)r = 288
⇒ [(22/7) + 2]r = 288
⇒ r = (288 x 7)/36 = 56

∴ Area of the park = (1/2)πr²
= (1/2) x (22/7) x 56 x 56
= 4928

Given that, a = 6
According to the formula,
Percentage increase in area
= 2a + [a²/100]%

Correct Option: B

Given that, a = 6
According to the formula,
Percentage increase in area
= 2a + [a²/100]%
= 2 x 6 + [36/100]%
= (12 + 0.36)%
= 12.36%

Distance covered in 1 round
= (Total Distance) / (Total round)

Correct Option: D

Distance covered in 1 round
= (Total Distance) / (Total round)
= (1.76 x 1000)/350
= 176/35 m

∴ 2πr = (1.76 x 100) / 35 cm
2π = Diameter = 17600 x 7/22 x 35 = 160 cm