Let the diagonals of the squares be 3x and 2x.
∴ Ratio of their areas = [(1/2) (3x²)] / [(1/2) (2x²)]

Correct Option: A

Let the diagonals of the squares be 3x and 2x.
∴ Ratio of their areas = [(1/2) (3x²)] / [(1/2) (2x²)] = 9/4

Area of the field =1215/135 = 9 hec
= 90000 m² [1 hec =10000 m²]
∴ Side of the field = √90000 = 300 m

Correct Option: C

Area of the field =1215/135 = 9 hec
= 90000 m² [1 hec =10000 m²]
∴ Side of the field = √90000 = 300 m
Perimeter of the field = 4 x 300 = 1200 m

Now, cost of putting a fence around field = (1200 x 75)/100 = ₹ 900

Ratio of area of 2 squares = (ratio of perimeter of 2 squares)²

Correct Option: C

Ratio of area of 2 squares = (ratio of perimeter of 2 squares)²
= (24/12)²
= 4

Required increment = 2a + [a² / 100] %

Correct Option: C

Required increment = 2a + [a² / 100] %
= 2 x 25 + [(25²)/100)] %
= 50 + (625/100)%
= 56.25%

Area of rhombus =(d₁ x d₂)/2

Correct Option: A

Area of rhombus =(d₁ x d₂)/2
=(1 x 1.5)/2 m²
= 0.75 m²