Area of the carpet = Area of the room

Correct Option: D

Area of the carpet = Area of the room
= 8 x 6 = 48 sq m

Width of the carpet = 75/100 = 3/4 m

Length of the carpet = 48 x (4/3)
= 16 x 4 = 64 m

∴ Cost of carpeting = 64 x 20 = ₹ 1280

l₁ = 20 cm, A₁ = 200 sq cm
∴ b₁ = 200/20 = 10 cm
Now, A₂ = 200 x 6/5 = 240 sq cm
b₂ = 10 cm
∴ l₂ = 240/10 = 24 cm

∴ Perimeter of new rectangle = 2(l₂ + b₂)

Correct Option: D

l₁ = 20 cm, A₁ = 200 sq cm
∴ b₁ = 200/20 = 10 cm
Now, A₂ = 200 x 6/5 = 240 sq cm
b₂ = 10 cm
∴ l₂ = 240/10 = 24 cm

∴ Perimeter of new rectangle = 2(l₂ + b₂)
= 2(24 + 10) = 2 x 34 = 68 cm

Area to the rectangular field = 12375/15 = 825 sq m
According to the question,
(L x B) = 825 [L = length and B = breadth]

Correct Option: C

Area to the rectangular field = 12375/15 = 825 sq m
According to the question,
(L x B) = 825 [L = length and B = breadth]
⇒ L x 25 = 825
∴ L = 825/25 = 33 m

According to the question,
4a = 68 [ where a = side]
∴a = 68/4 = 17 cm
∴ Required area = a²

Correct Option: C

According to the question,
4a = 68 [ where a = side]
∴a = 68/4 = 17 cm

∴ Required area = a²
= (17)² = 289 sq cm

a₁ = 68/4 = 17 cm
and a₂ = 60/4 = 15 cm
[ where a₁ and a₂ are sides]

According to the question,
Area of the third square = [(17)² - (15)² ]

Correct Option: C

a₁ = 68/4 = 17 cm
and a₂ = 60/4 = 15 cm
[ where a₁ and a₂ are sides]

According to the question,
Area of the third square = [(17)² - (15)² ]
= (17 + 15) (17 - 15)
= 32 x 2
= 64 sq cm

Let a₃ = Side of the third square.

According to the question, (a₃)² = 64 sq cm
∴ a₃ = √64 = 8 cm

∴ Perimeter of the third square = 4 x a₃ = 4 x 8 = 32 cm.