Area and Perimeter
-  Diagonals of a rhombus area 1 m and 1.5 m in lengths. The area of the rhombus is
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                        View Hint View Answer Discuss in Forum Area of rhombus =(d1 x d2)/2 Correct Option: AArea of rhombus =(d1 x d2)/2 
 =(1 x 1.5)/2 m2
 = 0.75 m2
-  If the diagonals of a rhombus are 4.8 cm 1.4 cm, then what is the perimeter of the rhombus?
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                        View Hint View Answer Discuss in Forum Perimeter of rhombus 
 = 2 √ d1 2 + d2 2Correct Option: BPerimeter of rhombus 
 = 2 √ d1 2 + d2 2
 = 2 √(4.8)2 + (1.4)2
 = 2 √23.04 + 1.96
 = 2 √25
 = 2 x 5 = 10 cm
-  Angles of a quadrilateral are in the ratio 3 : 4 : 5 : 8. The smallest angle is
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                        View Hint View Answer Discuss in Forum Sum of angles = 360° Correct Option: ALet First angle = 3k 
 Second angle = 4k
 Third angle = 5k and
 Fourth angle = 8k
 We know 3k + 4k + 5k + 8k = 360°
 ⇒ 20k = 360°
 ∴ k = 18 °
 Measure of smallest angle = 3k
 =3 x 18 °
 = 54 °
-  Floor of a square room of side 10 m is to be completely covered with square tiles, each having length 50 cm. The smallest number of tiles needed is ?
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                        View Hint View Answer Discuss in Forum Number of tiles needed = (Area of square room) / (Area of tile) Correct Option: CArea of square room = (10)2 = 100 sq m 
 = 100 x (100)2 sq cm
 = 100 x 100 x 100 sq cm
 Now, area of tiles = (50)2 = 50 x 50 sq cm
 ∴ Number of tiles needed = (Area of square room) / (Area of tile)
 = (100 x 100 x 100) / (50 x 50)
 = 400
 Hence, 400 tiles will be needed.
-  The perimeter of an isosceles triangle is 26 cm while equal sides together measure 20 cm. The third side and each of the equal sides are respectively.
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                        View Hint View Answer Discuss in Forum Let the third side be x. 
 According to the question,
 x + 20 = 26Correct Option: ALet the third side be x. 
 According to the question,
 x + 20 = 26
 ⇒ x = 26 - 20 = 6 cm
 ∴ Each equal side = 20/2 = 10 cm
 
	