Area and Perimeter
- Diagonals of a rhombus area 1 m and 1.5 m in lengths. The area of the rhombus is
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Area of rhombus =(d1 x d2)/2
Correct Option: A
Area of rhombus =(d1 x d2)/2
=(1 x 1.5)/2 m2
= 0.75 m2
- If the diagonals of a rhombus are 4.8 cm 1.4 cm, then what is the perimeter of the rhombus?
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Perimeter of rhombus
= 2 √ d1 2 + d2 2Correct Option: B
Perimeter of rhombus
= 2 √ d1 2 + d2 2
= 2 √(4.8)2 + (1.4)2
= 2 √23.04 + 1.96
= 2 √25
= 2 x 5 = 10 cm
- Angles of a quadrilateral are in the ratio 3 : 4 : 5 : 8. The smallest angle is
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Sum of angles = 360°
Correct Option: A
Let First angle = 3k
Second angle = 4k
Third angle = 5k and
Fourth angle = 8k
We know 3k + 4k + 5k + 8k = 360°
⇒ 20k = 360°
∴ k = 18 °
Measure of smallest angle = 3k
=3 x 18 °
= 54 °
- Floor of a square room of side 10 m is to be completely covered with square tiles, each having length 50 cm. The smallest number of tiles needed is ?
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Number of tiles needed = (Area of square room) / (Area of tile)
Correct Option: C
Area of square room = (10)2 = 100 sq m
= 100 x (100)2 sq cm
= 100 x 100 x 100 sq cm
Now, area of tiles = (50)2 = 50 x 50 sq cm
∴ Number of tiles needed = (Area of square room) / (Area of tile)
= (100 x 100 x 100) / (50 x 50)
= 400
Hence, 400 tiles will be needed.
- The perimeter of an isosceles triangle is 26 cm while equal sides together measure 20 cm. The third side and each of the equal sides are respectively.
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Let the third side be x.
According to the question,
x + 20 = 26Correct Option: A
Let the third side be x.
According to the question,
x + 20 = 26
⇒ x = 26 - 20 = 6 cm
∴ Each equal side = 20/2 = 10 cm