Area and Perimeter


  1. Diagonals of a rhombus area 1 m and 1.5 m in lengths. The area of the rhombus is









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    Area of rhombus =(d1 x d2)/2

    Correct Option: A

    Area of rhombus =(d1 x d2)/2
    =(1 x 1.5)/2 m2
    = 0.75 m2


  1. If the diagonals of a rhombus are 4.8 cm 1.4 cm, then what is the perimeter of the rhombus?









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    Perimeter of rhombus
    = 2 √ d1 2 + d2 2

    Correct Option: B

    Perimeter of rhombus
    = 2 √ d1 2 + d2 2
    = 2 √(4.8)2 + (1.4)2
    = 2 √23.04 + 1.96
    = 2 √25
    = 2 x 5 = 10 cm



  1. Angles of a quadrilateral are in the ratio 3 : 4 : 5 : 8. The smallest angle is









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    Sum of angles = 360°

    Correct Option: A

    Let First angle = 3k
    Second angle = 4k
    Third angle = 5k and
    Fourth angle = 8k

    We know 3k + 4k + 5k + 8k = 360°
    ⇒ 20k = 360°
    ∴ k = 18 °

    Measure of smallest angle = 3k
    =3 x 18 °
    = 54 °


  1. Floor of a square room of side 10 m is to be completely covered with square tiles, each having length 50 cm. The smallest number of tiles needed is ?









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    Number of tiles needed = (Area of square room) / (Area of tile)

    Correct Option: C

    Area of square room = (10)2 = 100 sq m
    = 100 x (100)2 sq cm
    = 100 x 100 x 100 sq cm

    Now, area of tiles = (50)2 = 50 x 50 sq cm
    ∴ Number of tiles needed = (Area of square room) / (Area of tile)
    = (100 x 100 x 100) / (50 x 50)
    = 400

    Hence, 400 tiles will be needed.



  1. The perimeter of an isosceles triangle is 26 cm while equal sides together measure 20 cm. The third side and each of the equal sides are respectively.











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    Let the third side be x.
    According to the question,
    x + 20 = 26

    Correct Option: A

    Let the third side be x.
    According to the question,
    x + 20 = 26
    ⇒ x = 26 - 20 = 6 cm
    ∴ Each equal side = 20/2 = 10 cm