Area and Perimeter
- The ratio of the area of the circumcircle and the incircle of a square is
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Ratio of the areas of the circumcircle and incircle of a square
= [(Diagonal)2π] / [(Side)2π]Correct Option: A
Ratio of the areas of the circumcircle and incircle of a square
= [(Diagonal)2π] / [(Side)2π]
= [(Side x √2)2] / (Side)2 = 2/1 or 2 : 1
- The radius of a circle is so increased that its circumference increased by 5%. The area of the circle, then increases by
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Increase in circumference of circle = 5%
∴ Increase in radius is also 5%.
Now, increase in area of circle = 2a + (a2/100) %Correct Option: B
Increase in circumference of circle = 5%
∴ Increase in radius is also 5%.
Now, increase in area of circle = 2a + (a2/100) %
Where, a = increase in radius= 2 x 5 + (5 x 5)/100 % = 10.25%
- The area of a circle is increased by 22 sq cm when its radius is increased by 1 cm. Find the original radius of the circle.
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Let original radius be r.
Then, according to the questions,
π (r + 1)2 - πr2 = 22Correct Option: C
Let original radius be r.
Then, according to the questions,
π (r + 1)2 - πr2 = 22
⇒ π x [(r + 1)2 - r2] = 22
⇒ (22/7) x (r + 1 + r ) x (r + 1 - r) = 22
⇒ 2r + 1 = 7
⇒ 2r = 6
∴ r = 6/2 = 3 cm
- Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 154 sq m.
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Length of to the rope = Radius of circle
According to the question,
πr2 = 154Correct Option: A
Length of to the rope = Radius of circle
According to the question,
πr2 = 154
∴ r2 = 154 x (7/22) = 7 x 7 = 49
∴ r = √49 = 7 m
- A man riding a bicycle, completes one lap of a circular field along its circumference at the speed of 14.4 km/h in 1 min 28 s. What is the area of the field?
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The man takes 3600 s for 14.4 km
The man will take 88 s for
14.4 x (88/3600) = 352/1000 km = 352 m
Now, circumference of circular field = 352 m
⇒ 2πr = 352 m
2 x (22/7) x r = 352
⇒ r = 56 m
Therefore, area of the field = πr2Correct Option: B
The man takes 3600 s for 14.4 km
The man will take 88 s for
14.4 x (88/3600) = 352/1000 km = 352 m
Now, circumference of circular field = 352 m
⇒ 2πr = 352 m
2 x (22/7) x r = 352
⇒ r = 56 m
Therefore, area of the field = πr2
= (22/7) x 56 x 56
= 8 x 22 x 56 m2
= 9856 sq m.