Algebra
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If xy + yz + zx = 1, then the value of 1 + y² is (x + y)(y + z)
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Given, xy + yz + zx = 1
∴ Expression = 1 + y² = 1 + y² = 1 + y² = 1 (x + y)(x + z) xy + xz + y² + yz 1 + y² Correct Option: D
Given, xy + yz + zx = 1
∴ Expression = 1 + y² = 1 + y² = 1 + y² = 1 (x + y)(x + z) xy + xz + y² + yz 1 + y²
