Algebra
- Find the co-ordinates of the mid point of a line segment joining the points (2, 4) and (6, 8) ?
-
View Hint View Answer Discuss in Forum
We know that co-ordinates of
x1 + x2 , y1 + y2 2 2 ⇒ x = 2 + 6 = 4 2 y = 4 + 8 = 6 2 Correct Option: B
We know that co-ordinates of
x1 + x2 , y1 + y2 2 2 ⇒ x = 2 + 6 = 4 2 y = 4 + 8 = 6 2
- For what value of k, the line kx + 3y + 6 = 0, will pass through the point (2, 4).
-
View Hint View Answer Discuss in Forum
As the line kx + 3y + 6 = 0
passes through (2, 4)
∴ k × 2 + 3 × 4 + 6 = 0
2k + 12 + 6 = 0
2k + 18 = 0
2k = –18 k = –9Correct Option: C
As the line kx + 3y + 6 = 0
passes through (2, 4)
∴ k × 2 + 3 × 4 + 6 = 0
2k + 12 + 6 = 0
2k + 18 = 0
2k = –18 k = –9
- In what ratio the line segment joining the points (2, 3) and (4, 6) is divided by y-axis?
-
View Hint View Answer Discuss in Forum
Let the co-ordinates of point be (0, y) because on y-axis, x is zero.
Let the ratio be k : 1
Using internal section formula, we get0 = 4k + 2 k + 1 k = - 2 4 k = - 1 2
–ve sign shows that point divides the line segment externally.Correct Option: D
Let the co-ordinates of point be (0, y) because on y-axis, x is zero.
Let the ratio be k : 1
Using internal section formula, we get0 = 4k + 2 k + 1 k = - 2 4 k = - 1 2
–ve sign shows that point divides the line segment externally.
- What is the equation of line passes through the point (3, 2) and make an angle of 45° with the line x – 2y = 3 ?
-
View Hint View Answer Discuss in Forum
Let the slope of line be m
Here,
θ = 45°m2 = - 1 = 1 - 2 2
We know that,1 = 2m - 1 2 + 3
⇒ 2 + m = 2m – 1
m = 3
∴ Equation of line be
y – y1 = m(x – x1)
y – 2 = 3(x – 3)
y – 2 = 3x – 9
3x – y – 7 = 0Correct Option: A
Let the slope of line be m
Here,
θ = 45°m2 = - 1 = 1 - 2 2
We know that,1 = 2m - 1 2 + 3
⇒ 2 + m = 2m – 1
m = 3
∴ Equation of line be
y – y1 = m(x – x1)
y – 2 = 3(x – 3)
y – 2 = 3x – 9
3x – y – 7 = 0
- A point R(h, k) divides a line segment between the axis in the ratio 1 : 2 what will be the equation of line ?
-
View Hint View Answer Discuss in Forum
Using internal section formula, we have
h = 1 × a + 2 × 0 1 + 2
⇒a = 3h
Similarly,k = 1 × 0 + 2 × b 1 + 2 k = 2b 3 b = 3k 2
∴ Equation of line bex + y = 1 a b ⇒ x + 2y = 1 3h 3k ⇒ x + 2y = 3 h k Correct Option: B
Using internal section formula, we have
h = 1 × a + 2 × 0 1 + 2
⇒a = 3h
Similarly,k = 1 × 0 + 2 × b 1 + 2 k = 2b 3 b = 3k 2
∴ Equation of line bex + y = 1 a b ⇒ x + 2y = 1 3h 3k ⇒ x + 2y = 3 h k