Both pUC and the bacterial own genome produce a faulty gene product of Lac Z gene. The lac Z fragment, whose synthesis can be induced by IPTG, is capable of intra-allelic complementation with a defective form of β-galactosidase enzyme encoded by host chromosome (mutation lacZDMI5)

Correct Option: A

Both pUC and the bacterial own genome produce a faulty gene product of Lac Z gene. The lac Z fragment, whose synthesis can be induced by IPTG, is capable of intra-allelic complementation with a defective form of β-galactosidase enzyme encoded by host chromosome (mutation lacZDMI5)

Given, Probability of finding the fragment in the library = 95% = 0.95 ​

Correct Option: D

Given, Probability of finding the fragment in the library = 95% = 0.95 ​

Given, size of the genome of E. coli ​​​= 4 × 10³kb = 4 × 10⁶ bp ​
Size of the DNA fragment = 5000 bp ​
Therefore, minimum number of independent recombinant clones required to represent the DNA fragment in a genomic library ​​ = (4 × 10⁶) / 5000 = 8 × 10²

Correct Option: C

Given, size of the genome of E. coli ​​​= 4 × 10³kb = 4 × 10⁶ bp ​
Size of the DNA fragment = 5000 bp ​
Therefore, minimum number of independent recombinant clones required to represent the DNA fragment in a genomic library ​​ = (4 × 10⁶) / 5000 = 8 × 10²

The given plasmid sequence is 5000bp long. When it is digested with Hind III, it produces 2 fragments of 1200bp and 3800bp. This means that Hind III cuts the plasmid in two different sites. So Hind III has 2 sites in plasmid. When digested with Bam HI, it produces one fragment of 5000bp. This means Bam HI has only 1 recognition site on the plasmid sequence. Eco RI cuts the fragment in two equal halves of 2500bp each. Hence Eco RI also has 2 sites of recognition on the plasmid.

Correct Option: A

The given plasmid sequence is 5000bp long. When it is digested with Hind III, it produces 2 fragments of 1200bp and 3800bp. This means that Hind III cuts the plasmid in two different sites. So Hind III has 2 sites in plasmid. When digested with Bam HI, it produces one fragment of 5000bp. This means Bam HI has only 1 recognition site on the plasmid sequence. Eco RI cuts the fragment in two equal halves of 2500bp each. Hence Eco RI also has 2 sites of recognition on the plasmid.

Glyphosate kills plants by interfering with the synthesis of the aromatic amino acids phenylalanine, tyrosine and tryptophan. It does this by inhibiting the enzyme 5-enolpyruvyl-shikimate-3-phosphate synthase (EPSPS), which catalyzes the reaction of shikimate-3-phosphate (S3P) and phosphoenolpyruvate to form 5-enolpyruvyl-shikimate-3-phosphate (ESP). Bromoxynil is a nitrile herbicide and one of its common degradation products (3, 5-dibromo-4-hydroxybenzoic acid) have been shown to undergo metabolic reductive dehalogenation by the microorganism. Sulfonylureas is used as Chlorimuron (Classic) for soybeans. Their site of action is Acetolactate synthase (ALS) enzyme. Dalapon is a synthetic herbicide and plant growth regulator. It is responsible for inhibition of lipid synthesis by acting on dehalogenase enzyme.

Correct Option: A

Glyphosate kills plants by interfering with the synthesis of the aromatic amino acids phenylalanine, tyrosine and tryptophan. It does this by inhibiting the enzyme 5-enolpyruvyl-shikimate-3-phosphate synthase (EPSPS), which catalyzes the reaction of shikimate-3-phosphate (S3P) and phosphoenolpyruvate to form 5-enolpyruvyl-shikimate-3-phosphate (ESP). Bromoxynil is a nitrile herbicide and one of its common degradation products (3, 5-dibromo-4-hydroxybenzoic acid) have been shown to undergo metabolic reductive dehalogenation by the microorganism. Sulfonylureas is used as Chlorimuron (Classic) for soybeans. Their site of action is Acetolactate synthase (ALS) enzyme. Dalapon is a synthetic herbicide and plant growth regulator. It is responsible for inhibition of lipid synthesis by acting on dehalogenase enzyme.